Simple trick is that there is only one pointer is mentioned and pointer is represented by *. So the answer is void(*ptr)().
Manas said:
(Dec 4, 2011)
@Saran you are great.
Patrick said:
(Jun 24, 2013)
Is there any difference between void *ptr() and void (*ptr)()?
Yug Verma said:
(Jul 24, 2013)
Yes, *ptr()-> ptr is a pointer function which returns void and void (*ptr)() -> ptr is a pointer to a function which returns void.
Siddu said:
(Nov 3, 2014)
"void *(*ptr)(*)" What does it mean?
Kiran Bhosale said:
(Feb 29, 2016)
This declaration is wrong and will give the compilation error "expected declaration specifiers or \'. \' before \'*\' token", i.e. there is no data type before * in (*).
If we replace this expression with something like this "void * (*ptr) (int *)", then it would be pointer to function that "returns void pointer and accepts integer pointer as an argument".
Vinay said:
(Aug 15, 2016)
@Saran
You are the great man your trick working everywhere. Thank you very much.
Rani said:
(Jun 6, 2018)
Please tell me the difference between pointer to function and pointer function.
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