Discussion :: Complicated Declarations - General Questions (Q.No.1)
| Dhiraj said: (Sep 22, 2010) | |
| What you have marked as answer is a pointer to an array of three character the correct answer will be char (*ptr)[3]; | |
| Bhavani said: (Dec 2, 2010) | |
| Yes (*ptr)[3] is correct. | |
| Tamil said: (Dec 19, 2010) | |
| Yes. You are right. Ptr is the array which contains 3 character pointer. | |
| Nagaraj said: (Dec 30, 2010) | |
| char *ptr[3]; It is an array wich consists of pointers. int *(ptr[20]); It is the pointer to array of 10 elements |
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| Nishu Nishant said: (Dec 31, 2010) | |
| Yes b option is correct *ptr[3] *(ptr[3])is a pointer to array of 3 elements where as *ptr[3] is an array consists of 3 pointers. agreed with nagraj.. |
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| Raj said: (Jun 1, 2011) | |
| Option b is absolutely correct no discussion at all. | |
| Richa Rao said: (Jul 10, 2011) | |
| It must be *ptr[2] as index start from 0th position. | |
| Kavinder Singh said: (Sep 20, 2011) | |
| Yes b option is correct *ptr[3] *(ptr[3])is a pointer to array of 3 elements where as *ptr[3] is an array consists of 3 pointers. agreed with nagraj and nishu |
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| Raju said: (Feb 9, 2012) | |
| char *ptr[3] is correct. There is 3 characters are defined in pointers. | |
| Ankita said: (Feb 26, 2012) | |
| In option (A) *ptr[3](); is a function means every pointer value is work as a function. In optinc (c) (*ptr[3])(); is a complete pointer function. In option (D) defines the pointer of pointer of array. So,finally option(B) is correct,which gives "An array of three pointers to chars". |
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| Gopi Krishnamraju said: (Mar 6, 2012) | |
| char *ptr[3]; ==>it means ptr is an array of three character pointers. char (*ptr)[3] ==>it means ptr is a pointer to the array which consists 3 3 characters as its elements |
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| Indu Mounika said: (May 19, 2012) | |
| ptr[3] shows an element of an aray. So *ptr[3] is a valid pointer |
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| Suman Pal said: (May 27, 2012) | |
| char *ptr[3] is right because it is a declaration of pointer of array, i.e., *(*(ptr+i)) where i is a character type of variable, store the address of char array type variable. | |
| Sakthi Priya said: (Mar 19, 2013) | |
| Option b is the correct answer. syntax for declaration "datatype_name variable_name;" Here char is the datatype name. *ptr[3] * represent the pointer. [3] represent the array. Finally, char *ptr[3] represents "An array of three pointers to chars". Option b is the correct answer for the given declaration. |
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| Shatakshi Sharma said: (Sep 1, 2014) | |
| Option (b) signifies that we are having a pointer variable ptr. [3] means 3 elements in array. And char *ptr[3]means we are having a pointer that is pointing to an array which holds the character. So option 2 is correct one. |
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| Naitik Gupta said: (Sep 30, 2014) | |
| I agree the the pointer hold variable like these char(*ptr[3]); | |
| Rajeshwar Reddy said: (Jan 5, 2015) | |
| char *ptr[3]; This means ptr is a array of size 3 (i.e. It contains 3 elements) , of type ptr (i.e. it contains 3 pointer elements) (i.e. it is an array of 3 pointers) , which is of type char? |
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| Vishal Sanghani said: (Oct 3, 2017) | |
| char *ptr[3] is the right one. | |
| Rohit Kumar said: (Aug 28, 2018) | |
| Here, convert all the options in postfix expression and read, the correct option will char *ptr[3];. | |
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