C Programming - Complicated Declarations - Discussion

Can any one explain me what does it actually mean by the above statements. Please.

The first statement is declaring two far pointers. But I didn't get the next declaration. Can any one explain me the next one?

Can anyone explain this with examples so that I could understand it more cleary?

char far *far *scr; -> It means scr is a far pointer to a far pointer to a char, or u can understand it as scr contains a far address of a far pointer to a char.

(far *scr) means scr is a far pointer.

(far *(far *scr)) means scr is a far pointer to a far pointer.

(char (far *(far *scr))) means scr is a far pointer to a far pointer to a char.

For better understanding assume it as,

scr(far type)-> *scr(far type)-> **scr(char type)

Take a example. Suppose address of **scr(char type) is 100, *scr(far type) is 200, scr(far type) is 300.

Now scr(far type) contains 200(address of *scr(far type)) and *scr(far type) contains 100(address of **scr(char type).

In 2nd Case: char far far** scr;

In this case scr(far type) contains 100(address of **scr(char type)) because you can see that (far **scr).

So we can say that the two declarations are different.

How can scr contain address of **scr ? scr is supposed to contain address of *scr, as far as I know at least : ).

Can you explain me both pointers?