C Programming - Command Line Arguments - Discussion

Friends, can anyone explain in linux?

Command line is nothing but the commands we give in a compiler to run the program finally for execution like ./a.out and so on.... Command line arguments is nothing but declaring the values in the command line which means that instead of providing values inside the code as int I; I am declaring after execution in the outer command line.

The argc will count the number of variables or the data you have input in the command line. *argv()(I do not have the other brace in my mobile please adjust) is to print or read the data you have provided on the command line.

Syntax to implement it in a program is as below,

Int main(int argc, char *argv())

Output:

If I am passing the values such as ./a.out 1 2 3 in the command line at the time of execution, the value if printed will be as;

Count(argc) will be 4. Command line ./a.out will be coming considered in as one count.
argv Will print all the values ./.a.out 1 2 3 to display.

What is the use of argc and argv?

Can you tell me the size in Linux?

How is the working of Command line argument?

What is the use of command line argument?

Please can anyone say explanation for this?

The full declaration of main looks like this:

int main ( int argc, char *argv[] )

The integer, argc is the argument count. It is the number of arguments passed into the program from the command line, including the name of the program.

The array of character pointers is the listing of all the arguments. argv[0] is the name of the program, or an empty string if the name is not available. After that, every element number less than argc is a command line argument. You can use each argv element just like a string, or use argv as a two dimensional array. argv[argc] is a null pointer.

What is use of agrc agrv?

Give brief discussion on command line arguments comparing with different os.

What is the use of command line argument and how can I use it ?