C Programming - Command Line Arguments - Discussion

Another question is :
What will be the output of the program (myprog.c) given below if it is executed from the command line?

cmd> myprog friday tuesday sunday

/* myprog.c */
#include<stdio.h>

int main(int argc, char *argv[])
{
printf("%c", *++argv[1]);
return 0;
}

For this answer is "r".

Can anyone explain difference in these ?

As the confusion is that in this question after ++ we move to next string and in another question as I mentioned above we move to one character.... why?

**argv is pointer to array of pointers.
*argv---->argv[0]---->myprog.
*argv+1-->argv[1]---->one.
.
.
.
argv having base address of "myprog".
++argv having base address of "one".
*++argv(dereference) prints "one".
**++argv(two times dereference) prints 'o'.

**++argv means argv[0] but this will give first chareacter of argv[0].. In this case the value is 0.
If you want second character of that same string you can write like this *(*(argv+0)+2)

I think here directory #include<stdlib.h> shouldn't mentioned.

But I tried in GCC compiler(linux) i got the out put like this

rajesh@rajesh-laptop:~$ vim prog.c
rajesh@rajesh-laptop:~$ cc prog.c
rajesh@rajesh-laptop:~$ ./a.out one two three
o
rajesh@rajesh-laptop:~$

**++argv will point to argv[1]

If again we do that (ie, **++argv) it will point to argv[2]

Here %c is the control string,So output will be the values present at their initial location[ie,if pointing to argv[1] it will show the character present at 0th location of argv[1]).

Here one thing to be taken into consideration is PRECEDENCE.Since ++ has high precedence over *(indrection),so pre-incrementation takes place first.and *argv==**argv,since both pointing to same address.
Khagesh Gupta alucidation in not so correct.

Moreover if we use array indexing here,then ++argv[i] means increment the value at argv[i] and display it.Andargv[i]++ means,value at argv[i] then increment the address using post increment protocol.

Seenu your answer is corretct n understand. Good explain.

I think seenu is correct because argv pointing to the first element that is myprog, when it is incremented (++ has higher priority than *), now it pointed to "one",but we have agian one * that will point to 'o'.

Seenu answer is correct.

Seenu your answer is acceptable, but Khagesh Gupta is correct.