C Programming - Command Line Arguments - Discussion

I think option A is the right answer.

Ans: argc (ARGument Count) is int and stores number of command-line arguments passed by the user including the name of the program. So if we pass a value to a program, value of argc would be 2 (one for argument and one for program name).

The value of argc should be non negative.

Argv (ARGument Vector) is array of character pointers listing all the arguments.

If argc is greater than zero, the array elements from argv[0] to argv[argc-1] will contain pointers to strings.

Argv[0] is the name of the program, After that till argv[argc-1] every element is command -line arguments.

Answer is true as its the count.

Ans: FALSE, read the question again carefully (must always be count of total arguments) it says we should give the count ie the total number of argument we are going to use. Argc stores only the number of argument given during the run time.

The argument supplied in command line not main();.

The, the answer is false.

No, the correct answer is false.

The argc parameter is the count of total command line arguments passed to the executable on execution (including the name of the executable as the first argument).

So the answer is true.

@Swetha yeah correctly said me too was mistaken by the language used.

The question asked is "First argument to be supplied at command-line". They are asking If we need supply any such argument. So it's clearly false.

Hey guys the answer is false.

Because the question asked is first argument in command line not to main().

Hope you understand. :).

1st argument is always program name.