C Programming - Command Line Arguments - Discussion
Discussion Forum : Command Line Arguments - Find Output of Program (Q.No. 7)
7.
What will be the output of the program if it is executed like below?
cmd> sample
cmd> sample
/* sample.c */
#include<stdio.h>
int main(int argc, char **argv)
{
printf("%s\n", argv[argc-1]);
return 0;
}
Discussion:
15 comments Page 2 of 2.
Gandhi said:
1 decade ago
thanks himadri
Handyrockzz said:
1 decade ago
tanks pallvi
Raksha said:
1 decade ago
thanks pallav.........
PallavidBest said:
2 decades ago
The argv is a double pointer to character array string which is taken as input on command line. argc is total number of argument taken on command line. Here argc=1. So argv[argc-1]=argv[0], argv[0] will refer to sample. So the output.
(1)
Prajesh Bhushan said:
2 decades ago
Can't understand. Please help me understand the logic behind it.
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