C Programming - C Preprocessor - Discussion
Discussion Forum : C Preprocessor - Find Output of Program (Q.No. 4)
4.
What will be the output of the program?
#include<stdio.h>
#define JOIN(s1, s2) printf("%s=%s %s=%s \n", #s1, s1, #s2, s2);
int main()
{
char *str1="India";
char *str2="BIX";
JOIN(str1, str2);
return 0;
}
Discussion:
35 comments Page 1 of 4.
Sruthi said:
9 years ago
The rule is if the parameter name is preceded by a # in the macro expansion, the combination (of # and parameter) will be expanded into a quoted string with the parameter replaced by the actual argument. This can be combined with string concatenation to print desired the output.
(2)
Poovarasan said:
6 years ago
Not getting it. Please explain me.
(1)
Saravana said:
8 years ago
# is called Stringizing operator, whatever you pass (here variable name ) is converted to String, so result come with the variable name.
(1)
Jayesh said:
8 years ago
This because there we use the JOIN STRING FUNCTION in which the str1 print& then next str2join the str1.
Because we have to use join string function.
Because we have to use join string function.
(1)
Natasha said:
1 decade ago
# is a stringizing operator. it will convert the argument into string.
eg #define df(a) printf(#a)
main()
{
int b=7;
df(b);
}
This will give result
b
as the statement df(b) was converted to printf("b");
eg #define df(a) printf(#a)
main()
{
int b=7;
df(b);
}
This will give result
b
as the statement df(b) was converted to printf("b");
(1)
Nandini said:
1 decade ago
#is name of the variable. So, if #str1 gives str1 content.
Sparsh610 said:
1 decade ago
It only works in macros ?
Or we can print them in main function too ?
Or we can print them in main function too ?
Gaurav Kumar Garg said:
1 decade ago
@Sachin Kumar.
Its your choice you can also remove semicolon. without semi colon it will also work.
With semi colon in macro
You can also call JOIN(str1, str2) <--- no semicolon.
Its your choice you can also remove semicolon. without semi colon it will also work.
With semi colon in macro
You can also call JOIN(str1, str2) <--- no semicolon.
Avinash said:
1 decade ago
# symbol is used to print the actual arguments that are passed to function.
Sunil Kothari said:
1 decade ago
#include<stdio.h>
#define cube(x) (x*x*x)
void main()
{
int a,b =3;
a= cube(++b);
printf("%d \n %d", a, b);
}
Output:
-------
150
6
Please explain above program?
#define cube(x) (x*x*x)
void main()
{
int a,b =3;
a= cube(++b);
printf("%d \n %d", a, b);
}
Output:
-------
150
6
Please explain above program?
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