C Programming - Bitwise Operators - Discussion

int a=8,b=2; printf("%d",a>>b); explain.

Any one can explain simple masking program?

In bitwise operator we are comparing in between 2 digits.

Ex : 1|0 = 1.

But in logical operator we are comparing in between two conditions/ 2 values.

Ex : 1||1 = 1.

Let me explain the answer.

The input value is 255 00000000 11111111

If we want to turn on the 10th bit means

The turn of value is 00000010 00000000

00000000 11111111
00000010 00000000 | operation
------------------
00000010 11111111
------------------

If we want to on particular bit OR operation is performed.

As we know to turn on any state we need the output as 1.

We can easily get it if we use the OR (|) operator. As only a single 1 and all others as 0's would also result in the on state if we use the (|) operator.

@Khushboo.

Logical OR operator is operated on two values that are True(T or 1) and False(F or 0)
i.e --(1)-- || --(2)--

(1),(2) are any expression that gives 0 or 1

Ex:

1||1=1
1||0=1
0||1=1
0||0=0

But if we see bit-wise OR operator ,it operated on any two integer values x,y.

Ex: x|y

In this every integer is represented by binary numbers, then OR operator is operated on each bit.

Ex:

10|6 gives 14 ; 10||6 gives 1
10 --> (1010) ; true || true =true
6 --> (0110) ;
---------------- ;
14 --> 1110 ;

What is difference between logical and bitwise OR?

This answer is wright because "|"this operator is called OR. It is a particular turning operator.

What is difference between logical and bitwise OR?

|| it will call as logical OR.here OR truth table is true false=true, true true=true.so here OR operator is on a particular bit in a number.