# C Programming - Bitwise Operators - Discussion

### Discussion :: Bitwise Operators - General Questions (Q.No.2)

2.

Which bitwise operator is suitable for turning off a particular bit in a number?

 [A]. && operator [B]. & operator [C]. || operator [D]. ! operator

Explanation:

No answer description available for this question.

 Ravi(Bit Mesra Cse_2K7) said: (Oct 21, 2010) Any bit AND(&) with 0 will give a zero .i.e. will turn that particular bit OFF.

 Suhas . U said: (Nov 26, 2010) Which bit u want make 0 ...make only that bit 0 n allother bits 1... ex:-to make 3rd bit 0 use &operator with one operand as11110111

 Arjun Prasad said: (Feb 28, 2011) To make above operand you take a number 1 and then shift its only set bit to the number of the bit you want to turn off(1<<3) and then take AND with given number.

 Arjun Prasad said: (Feb 28, 2011) ~(1<<"bit position") is the operand

 Sohan Lal Mits Gwalior said: (Mar 1, 2011) Bitwise 'AND' of any bit with zero bit is always zero (off).

 Kumar said: (Apr 23, 2011) Could anyone give an explanation in brief with example the above examples could not be understood

 Sundar said: (Apr 24, 2011) @Kumar Let me explain. How to turn off only the 4th bit (from right) in a 16-bit binary number? unsigned int intFalg4Off = 0xfff7; //Hex = 0xfff7 (or) Decimal = 65527 (or) Binay = 11111111 11110111 unsigned int intInputVal = 255; //Decimal = 255 (or) 0x00ff (or) 00000000 11111111 unsigned int Result = intInputVal & intFalg4Off; The result will be the & (AND operation) between the binary numbers given below : 11111111 11110111 00000000 11111111 00000000 11110111 (Decimal = 247 or Hex = 0x00f7) Here 4th bit of the given input has been turned off. Therefore, intResult will contain the value 247. Hope this will help you. Have a nice day!

 Ramya said: (Jul 8, 2011) Thanks sundar.

 Anuradha Sharma said: (Sep 2, 2011) If we take any bit AND (&) with 0 will give a zero. (i.e) Will turn that particular bit OFF.

 Saurav said: (Sep 5, 2011) But! why will && not work?

 Heena said: (Sep 16, 2011) Because && is a logical operator not a bitwise (bitwise is a operator that takes single bit at a time).

 Bari said: (Sep 22, 2011) How to work bitwise ?

 Vinod Basi said: (Nov 4, 2011) Sorry, I know this is an outdated thread... But just saw Mr.Gaurav's doubt to be one which I had a days back. Here is a simple explanation, correct me if am wrong. @Saurav Its like && and || are logical operators, evaluting true statements. Eg: Sachin && Sehwag opens batting, It returns true(1) only if both the guys are present to open the game. Else False(0) Sachin || Sehwag, return true(1), if either Sachin or Sehwag accompanied by someone else opens the game. Else false(0) & and | are bitwise operators, High and Low AND, OR gates truth table pretty much explains it. Eg: 2 & 3 (AND) 010 & 011 ------ 010 2 | 3 (OR) 010 | 011 ------ 011 Bitwise operators can be predominantely found in Embedded design, to find the status (ON or OFF) of a bit in a system. Hope this explains... Cheers...

 Athi said: (Nov 29, 2011) I have 1 doubt please tell me how to find the status of a bit ie char s; Then write a c program to find the status of 170th bit.

 Satyaprakash said: (Jan 12, 2012) Turn off operator in bitwise operators is and because it turns 1&0 and 0&1 into turn off(that is o). |(OR) bitwise turns preceeded operations into turn on(that is 1). Hence AND IS turn off operator.

 Naveen Kumar Ramisetty said: (Feb 2, 2012) Thanks ramya.

 Deepanwita said: (Jul 26, 2012) Bitwise operator is more easily been applied than the logical operator.

 Mouni said: (Sep 3, 2012) Please explain how to convert hexa decimal into binary.

 Saiprabha said: (Sep 7, 2012) If you want to off the bit means u want to make it ZERO it is possible in only & condition because in & if 1 1 o/p-1 else 0

 Dinesh said: (Sep 18, 2012) I explain in simple manner bit wise & truth table ========================= a b z ========================= 0 0 0 1 0 0 1 1 1 0 1 0 ========================== only one condition satisfyied foe on bit excpt bit value is off position

 Prema Latha.S said: (Sep 28, 2012) Bitwise AND operator (&), one's complement operator(~) Example: To unset the 4th bit of byte_data or to turn off a particular bit in a number. Explanation: Consider, Material from Interview Mantra. Subscribe to free updates via email. char byte_data= 0b00010111;byte_data= (byte_data)&(~(1<<4)); 1 can be represented in binary as 0b00000001 = (1<<4) << is a left bit shift operator, It shifts the bit 1 by 4 places towards left. (1<<4) becomes 0b00010000 And ~ is the one's complement operator in C language. So ~(1<<4) = complement of 0b00010000 = 0b11101111 Replacing value of byte_data and ~(1<<4) in (byte_data)&(~(1<<4)); We get (0b00010111) & (0b11101111) Perform AND operation to below bytes. 00010111 11101111 ----------- 00000111 ----------- Thus the 4th bit is unset.

 Umesh said: (Jun 25, 2013) How to convert hexadecimal into binary? Answer: 1) Take the hexa decimal no. and calculate it decimal value first. 2) Convert decimal number into binary having 4 digit. 3) Repeat 1 and 2 until number is not end. e.g. A2F for A decimal is 10. and 10 = 1010 in binary in the same way. 2 = 2 in decimal and in binary 0010. F = 15 in decimal and in binary 1111. So Hexa(A2F) = Binary (1010 0010 1111).

 Sudheer said: (Aug 23, 2013) Hai friends I am new to C language programming I am unable to understand the logics in this languages in bitwise operation can any explain this in simple way please?

 Kannan P said: (Sep 3, 2013) Given 4 option A and C not a bit-wise operator. B and D is a bit-wise operator. If you use D it will totally changed the values in high to low and low to high. But use & operator mask bit. We can change where ever you want.

 Ajarmani said: (Sep 6, 2013) @Sudheer. The basics of bitwise operation is: 1 & 1 = 1 1 & 0 = 0 0 & 1 = 0 0 & 0 = 0 1 | 1 = 1 1 | 0 = 1 0 | 1 = 1 0 | 0 = 0 Using this we will solve an example. 5 & 3 1.Convert to binary 101 & 011. 2. Now apply bitwise operation: 1 0 1 = 5 & & & 0 1 1 = 3 _____ 0 0 1 = 1 Hence 5 & 3 = 1.

 Ranjana said: (Sep 19, 2013) Any bit AND(&) with 0 will give a zero .i.e. will turn that particular bit OFF.

 Mallikarjun said: (Aug 25, 2014) Bitwise & is used for masking bits i.e 1 can be done 0.

 Sudha said: (Nov 6, 2014) And operator follow a multiple mechanism. So Zero the position will be off, the OR operator addition mechanism.

 Apshana said: (Jul 15, 2015) Why && will not be answer? And tell me what is the difference between & and &&?

 Nkandu said: (Sep 26, 2015) I am new to c programming I don't understand it can someone please help me.

 Simanta said: (Nov 7, 2015) For an example: int a,b,c; a=5; b=6; c=a&&b; //In this situation when a and b having any -ve or +ve value. Then it is taken as 1. So c = 1 && 1=1. Rather then '0' all value are taken as 1. d = a & b; //In this situation the operation is perform between every binary bit of a and b. So a = 5 = 101. b = 6 = 110 so d = 100 = 4. That is why '&&' called logical operator and '&' called bit-wise operator.

 Deepak_Bboy said: (Dec 25, 2015) AND. 0 & 0 = 0 OFF. 1 & 0 = 0 OFF. OR. X & 0 = 0 OFF. OR. Input & 0 = 0 OFF. BUT OR. 0| 0 = 0. 0| 1 = 1. 1| 0 = 1. 1| 1 = 1. You can't OFF a 1 (input). As you can see above.

 Pritam said: (Jan 12, 2016) If we read question carefully what I understood is that if I want to turn off the bit. i.e First bit is on means 1. To turn off it I use negation so that it will turn off.

 Emanuel said: (Sep 29, 2016) I think ^ operator.

 Shanme said: (Oct 18, 2016) Simply we can say, on the given option everything is logical operator, the only bitwise operator is &, So answer &.

 Sateesh said: (Mar 6, 2017) I think whether in AND case both are true then only particle turned on. So I think OR case is the correct answer. Anyone explain it.

 Gafoor said: (Nov 23, 2017) how to work & operator in the program? Can anyone explain with an example, please?

 Anusha said: (Dec 13, 2017) ! operator makes the non zero number into zero. thus (!52)=0,!65=0,........... but ! (0)=1 why don't the answer is ! operator? Can anyone explain?

 Ruhi said: (Oct 26, 2018) Thanks all for explaining this.