C Programming - Bitwise Operators - Discussion

I am not thinking that it is a true answer.

There is no logic and bitwise & binary operator it takes min 2 operands, so how it check that whether a particular bit is on or off.

What is the use of || operator? Please explain me friends.

The output of logical operators gives 0/1.
The output of bitwise operators gives decimal of given numbers.

Example:

(a=5)&&(b=2)
the a&b are both are non-zero numbers it gives result as 1
if
(a=5)&&(b=0)

So result is 0.
Because one of operands b is zero.
But in bitwise operators, the operation goes on the binary number of given operands.

if
(a=2)&(b=1)
convert the 2,1 binary numbers in 4 bits that 8421;
2's binary number 0010
1's binary number is 0001
0&0=0
0&0=0
1&0=0
0&1=0


Output is 0

@Pritam & @Guru Sai.

There is no option of OR(|) in the given question.

How it be? Explain.

0 | 0 = 0.

1 | 0 = 1.

So, why can't we use like this?

I don't understand, why always & operator use. Truth table of | or operator also provides logical relation then why always &?

Can anyone explain bitwise operators by writing a program?

Then why can't we use?

@Dimple,

You are correct. Why we can used (|) instead of (&)?

I think that the right answer is D.

For eg:

If I write if(a) then it is 1.

If I write if(!a) then it is 0.