C Programming - Bitwise Operators - Discussion
Discussion Forum : Bitwise Operators - Find Output of Program (Q.No. 4)
4.
If an unsigned int is 2 bytes wide then, What will be the output of the program ?
#include<stdio.h>
int main()
{
unsigned int a=0xffff;
~a;
printf("%x\n", a);
return 0;
}
Discussion:
47 comments Page 1 of 5.
Ranjit said:
2 decades ago
Can any explain why ~operator has no effect here?
Sundar said:
2 decades ago
Hi Ranjit,
The modified value is not stored in 'a' back.
If we write like this a = ~a; we can find the changes by ~ operator.
Hope you understand it. Have a nice day!
The modified value is not stored in 'a' back.
If we write like this a = ~a; we can find the changes by ~ operator.
Hope you understand it. Have a nice day!
Pratik said:
1 decade ago
Can you explain in detail how answer is a?
Youssef said:
1 decade ago
0xfff = 1111 1111 1111 1111
and ~a is not a=~a
~a dose not affect the value of a
and ~a is not a=~a
~a dose not affect the value of a
Nirlep said:
1 decade ago
~a does not assigned any where yaar
so simple
so simple
Naumi said:
1 decade ago
It is like Lvalue is not present therr ...Lvalue is a conatiner/variable on left side of the expression.....which would have contained the value of ~a.
Sohan lal mits said:
1 decade ago
Only ~a does not restored the value in a so finaly output is same as previous as assign.
Nikita said:
1 decade ago
Is ~a; a valid statement?
If we write a++ or ++a there is still no left sise variable but it changes 'a' so why not ~a changes 'a'.
If we write a++ or ++a there is still no left sise variable but it changes 'a' so why not ~a changes 'a'.
Chandu said:
1 decade ago
The modified variable(~a) must be assigned to another or same(a) variable. then only value will be changed.
Ex:-
a=~a;
Ex:-
a=~a;
Durgaprasad said:
1 decade ago
And also NONE OF THE GIVEN ANSWERS ARE CORRECT... becoz when int size is 2 and print that int it will print ffffffff(8 fs).. I have checked it .. So be careful...
Answer here is ffffffff
Answer here is ffffffff
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