C Programming - Bitwise Operators - Discussion
Discussion Forum : Bitwise Operators - Find Output of Program (Q.No. 2)
2.
If an unsigned int is 2 bytes wide then, What will be the output of the program ?
#include<stdio.h>
int main()
{
unsigned int m = 32;
printf("%x\n", ~m);
return 0;
}
Discussion:
35 comments Page 3 of 4.
Raja said:
1 decade ago
~m= ones compliment of m.
Replace binary form of 32 with its compliment form.
Replace 0 with 1 and 1 with 0.
Replace binary form of 32 with its compliment form.
Replace 0 with 1 and 1 with 0.
Sudheer kumar raina said:
1 decade ago
1) 32--> in binary--> for 2 bytes --> 0000 0000 0010 0000.
2) Now ~m makes all 0's to 1's and viceversa. ---> 1111 1111 1101 1111.
3) Now lets convert them into hexa, as %x is specified as format specifier.
4) Now the output in 2nd step becomes "f (15) f (d (13) f" in hexa decimal.
5) Finally "ffdf" is the answer.
2) Now ~m makes all 0's to 1's and viceversa. ---> 1111 1111 1101 1111.
3) Now lets convert them into hexa, as %x is specified as format specifier.
4) Now the output in 2nd step becomes "f (15) f (d (13) f" in hexa decimal.
5) Finally "ffdf" is the answer.
Divya said:
1 decade ago
Thanks for your explanation.
Abani said:
1 decade ago
Binary representation of 32 in 16bit(turbo c) is 0000000000100000
Hence 1's complement of 32 is 1111111111011111 and whose hexadecimal form is FFDF which is option C.
Hence 1's complement of 32 is 1111111111011111 and whose hexadecimal form is FFDF which is option C.
Munni said:
1 decade ago
m=32
Hence C is answer.
In binary: 0000 0000 0010 0000
Hence ~m : 1111 1111 1101 1111
f f d f
Hence C is answer.
NEERAJ KUMAR said:
1 decade ago
Thank nitu
Shilpa said:
1 decade ago
Thanks Neetu & Sudheer Kumar Raina, very well explianed.
Kishore said:
1 decade ago
Bcoz purpose of ~ will act as NOT operator and hence in binary equivalent as shows as 1111 1111 1101 1111.... hence option c..
Sanjay said:
1 decade ago
Good explain munni.
Chinnu said:
1 decade ago
Thanks munni thanku so much.
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