C Programming - Bitwise Operators - Discussion
Discussion Forum : Bitwise Operators - Find Output of Program (Q.No. 2)
2.
If an unsigned int is 2 bytes wide then, What will be the output of the program ?
#include<stdio.h>
int main()
{
unsigned int m = 32;
printf("%x\n", ~m);
return 0;
}
Discussion:
35 comments Page 2 of 4.
Sanjay said:
1 decade ago
Good explain munni.
Chinnu said:
1 decade ago
Thanks munni thanku so much.
Jayakrishana said:
1 decade ago
Thanks for you explanation Sudheer Kumar Raina.
Jagajjeevan said:
1 decade ago
~a=-(a+1)
~32=-(32+1)=-33
Binary of 33 : 0000 0000 0001 0001
1's of 33 : 1111 1111 1110 1110
2's of 33(-33): 1
1111 1111 1110 1111
f f d f
~32 is ffdf
~32=-(32+1)=-33
Binary of 33 : 0000 0000 0001 0001
1's of 33 : 1111 1111 1110 1110
2's of 33(-33): 1
1111 1111 1110 1111
f f d f
~32 is ffdf
Vignesh said:
1 decade ago
What does "f"&"d" mean and any thing others.
Chelsi said:
1 decade ago
How did you took m=32 as in binary: 0000 0000 0010 0000 please explain me?
Naveen said:
1 decade ago
But in the compiler provided by the indiabix.com.
The output is ffffffdf.
Can anyone explain why?
The output is ffffffdf.
Can anyone explain why?
Raina said:
1 decade ago
HOW TO WRITE .
32 = 0000 0000 0010 0000.
Can anyone explain this?
32 = 0000 0000 0010 0000.
Can anyone explain this?
Sravanthi said:
1 decade ago
Assume each digit from right to left as 2 power i.
Where i =0,1,2...
Now 32 is 0000 0000 0010 0000.
Which mean 0*(2 power 0)+0*(2 power 1)+0*(2 power 2)+0*(2 power 3)+0*(2 power 4)+1*(2 power 5)+0*(2 power 6)+..
Where i =0,1,2...
Now 32 is 0000 0000 0010 0000.
Which mean 0*(2 power 0)+0*(2 power 1)+0*(2 power 2)+0*(2 power 3)+0*(2 power 4)+1*(2 power 5)+0*(2 power 6)+..
Gaurav bisht said:
1 decade ago
Since unsigned 2 byte m = 32 can be represented as:
0000 0000 0010 0000
To do ~m means just complimenting m i.e.
~m = 1111 1111 1101 1111
In Hexa 1111 = f and 1101 = d
Therefore result is ffdf.
0000 0000 0010 0000
To do ~m means just complimenting m i.e.
~m = 1111 1111 1101 1111
In Hexa 1111 = f and 1101 = d
Therefore result is ffdf.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers