C Programming - Arrays - Discussion
Discussion Forum : Arrays - Find Output of Program (Q.No. 1)
1.
What will be the output of the program ?
#include<stdio.h>
int main()
{
int a[5] = {5, 1, 15, 20, 25};
int i, j, m;
i = ++a[1];
j = a[1]++;
m = a[i++];
printf("%d, %d, %d", i, j, m);
return 0;
}
Answer: Option
Explanation:
Step 1: int a[5] = {5, 1, 15, 20, 25}; The variable arr is declared as an integer array with a size of 5 and it is initialized to
a[0] = 5, a[1] = 1, a[2] = 15, a[3] = 20, a[4] = 25 .
Step 2: int i, j, m; The variable i,j,m are declared as an integer type.
Step 3: i = ++a[1]; becomes i = ++1; Hence i = 2 and a[1] = 2
Step 4: j = a[1]++; becomes j = 2++; Hence j = 2 and a[1] = 3.
Step 5: m = a[i++]; becomes m = a[2]; Hence m = 15 and i is incremented by 1(i++ means 2++ so i=3)
Step 6: printf("%d, %d, %d", i, j, m); It prints the value of the variables i, j, m
Hence the output of the program is 3, 2, 15
Discussion:
39 comments Page 1 of 4.
Anandesh said:
8 months ago
2,3,20 is the answer.
Tharun parsa said:
1 year ago
The answer is 3,2,15.
Because
i=++a[1]=++1 (since a[1]=1) then i=2
i=2,and a[1]=2 (because pre-increment )
j=a[1]++=2++ (since a[1]=2 here)
j=2 and a[1]=3
m=a[i++] that is i=2 and only i value will be taken in the square bracket then it will be incremented
m=a[2++]
which means m=a[2 ]and then i value increases by 1 then i =3
So, m=a[2]=15
Hence the output is 3,2,15.
Because
i=++a[1]=++1 (since a[1]=1) then i=2
i=2,and a[1]=2 (because pre-increment )
j=a[1]++=2++ (since a[1]=2 here)
j=2 and a[1]=3
m=a[i++] that is i=2 and only i value will be taken in the square bracket then it will be incremented
m=a[2++]
which means m=a[2 ]and then i value increases by 1 then i =3
So, m=a[2]=15
Hence the output is 3,2,15.
(6)
Shantaras said:
3 years ago
Sir,
M=a (2) taken why not a (3). (because I is incremented).
M=a (2) taken why not a (3). (because I is incremented).
(3)
Jaydeep B said:
3 years ago
I think the correct answer would be 2, 3, 15.
(17)
Kaviya.p said:
3 years ago
@Rosh.
The value of j is not incremented the a[1] value is incremented see its because of post incremented.
The value of j is not incremented the a[1] value is incremented see its because of post incremented.
(1)
Rosh said:
5 years ago
@Mohanapriya @Rupinderjit Singh
It was quit understandable explanation but still, I have a doubt j and m both are using post increment then why only m is incremented (when we reach to print statement ). Why not j?
Please explain about it.
It was quit understandable explanation but still, I have a doubt j and m both are using post increment then why only m is incremented (when we reach to print statement ). Why not j?
Please explain about it.
Mainak said:
6 years ago
I am not understanding step 5. Please explain it clearly.
R.Amirthavarshini said:
6 years ago
I think 2, 3, 20 is the answer.
(4)
Dev said:
7 years ago
Thanks @Gayathri.
Anita said:
7 years ago
Please explain it to me to understand the concept of this.
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