C Programming - Arrays - Discussion
Discussion Forum : Arrays - Find Output of Program (Q.No. 3)
3.
What will be the output of the program ?
#include<stdio.h>
int main()
{
void fun(int, int[]);
int arr[] = {1, 2, 3, 4};
int i;
fun(4, arr);
for(i=0; i<4; i++)
printf("%d,", arr[i]);
return 0;
}
void fun(int n, int arr[])
{
int *p=0;
int i=0;
while(i++ < n)
p = &arr[i];
*p=0;
}
Answer: Option
Explanation:
Step 1: void fun(int, int[]); This prototype tells the compiler that the function fun() accepts one integer value and one array as an arguments and does not return anything.
Step 2: int arr[] = {1, 2, 3, 4}; The variable a is declared as an integer array and it is initialized to
a[0] = 1, a[1] = 2, a[2] = 3, a[3] = 4
Step 3: int i; The variable i is declared as an integer type.
Step 4: fun(4, arr); This function does not affect the output of the program. Let's skip this function.
Step 5: for(i=0; i<4; i++) { printf("%d,", arr[i]); } The for loop runs untill the variable i is less than '4' and it prints the each value of array a.
Hence the output of the program is 1,2,3,4
Discussion:
25 comments Page 3 of 3.
Preeti said:
6 years ago
In fun(4, arr) function , there is no printf statement. So it does not affect output.
Lingam said:
8 years ago
Please explain the while loop condition not used please explain.
Rani said:
1 decade ago
Why the function fun(4,arr) does not effect the output ?
Subbu said:
1 decade ago
Please tell me the the difference between *p=0 and **p=0
Meghana said:
1 decade ago
What is the use of p = &arr[i]; ?
Post your comments here:
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