C Programming - Arrays - Discussion
Discussion Forum : Arrays - Find Output of Program (Q.No. 3)
3.
What will be the output of the program ?
#include<stdio.h>
int main()
{
void fun(int, int[]);
int arr[] = {1, 2, 3, 4};
int i;
fun(4, arr);
for(i=0; i<4; i++)
printf("%d,", arr[i]);
return 0;
}
void fun(int n, int arr[])
{
int *p=0;
int i=0;
while(i++ < n)
p = &arr[i];
*p=0;
}
Answer: Option
Explanation:
Step 1: void fun(int, int[]); This prototype tells the compiler that the function fun() accepts one integer value and one array as an arguments and does not return anything.
Step 2: int arr[] = {1, 2, 3, 4}; The variable a is declared as an integer array and it is initialized to
a[0] = 1, a[1] = 2, a[2] = 3, a[3] = 4
Step 3: int i; The variable i is declared as an integer type.
Step 4: fun(4, arr); This function does not affect the output of the program. Let's skip this function.
Step 5: for(i=0; i<4; i++) { printf("%d,", arr[i]); } The for loop runs untill the variable i is less than '4' and it prints the each value of array a.
Hence the output of the program is 1,2,3,4
Discussion:
25 comments Page 1 of 3.
PRADEEP said:
1 decade ago
Here i increment to 4 p is assigned as it is post increment. p=&a[4],so it put outside the array limit, .In the main array it is not effected.
Pradeep Kumar said:
1 decade ago
In the function fun condition while loop is i++<n i.e it will compare the value first then increment(post increment), then enter the loop.last iteration it will assign p with address of 5th element of arr[4].so the main function arr values not effected. But it will produce run time error or segmentation fault at *p=0; after while loop.because accessing the memory which is not allocated or allowed.
Kaustubh said:
1 decade ago
This code causes runtime error. The function func modifies memory which is beyond the scope of the array. This can corrupt the program stack.
Rani said:
1 decade ago
Why the function fun(4,arr) does not effect the output ?
Payal said:
1 decade ago
Pradeep kumar what do you mean by "But it will produce run time error or segmentation fault at *p=0; after while loop. Because accessing the memory which is not allocated or allowed. ".
Deepak said:
1 decade ago
Can anyone tell why we use fun(4,arr) instead of fun(4,arr[]); when we use fun(4,arr[]) then it will show syntax error.
Tell me how nemory is allocated in this program.
Tell me how nemory is allocated in this program.
Rupinderjit said:
1 decade ago
Here is the Simple solution.The "i" in the function definition is local to that block.It's scope is only inside the curly braces of function definition.
And the "i" in main program doesn't knows the "i" in function definition.So function dentition's "i" has no effect on output,which implies fun(4,arr[]) has no effect on the output.
So the output is 1 2 3 4.
And the "i" in main program doesn't knows the "i" in function definition.So function dentition's "i" has no effect on output,which implies fun(4,arr[]) has no effect on the output.
So the output is 1 2 3 4.
Karthi said:
1 decade ago
Void function doesnt return anything, if the function is int then what will be the output.
Yogesh said:
1 decade ago
Whenever an array is passed as argument to a function, the pointer to the first element is actually passed. Then why the function fun () has no affect on its output. Please help.
Harsha kumar said:
1 decade ago
The code will compile witout any error but it will lead to out of bound condition at run time so the program crashes.
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