C Programming - Arrays - Discussion
Discussion Forum : Arrays - General Questions (Q.No. 2)
2.
What does the following declaration mean?
int (*ptr)[10];
int (*ptr)[10];
Discussion:
65 comments Page 5 of 7.
Gautam jangra said:
2 decades ago
int (*ptr)[10]
also we can write it as
int *ptr[10]
this line says that ptr is a pointer type variable which stores the address of first element of a 10 elements array list
as we know that array is continous memory type allocation.....
also we can write it as
int *ptr[10]
this line says that ptr is a pointer type variable which stores the address of first element of a 10 elements array list
as we know that array is continous memory type allocation.....
Neeraj awasthi said:
2 decades ago
If () is not there then int *ptr[] start with [] and it means array of pointers of type integers.
Nagaraj said:
2 decades ago
The below program explains tat the starting address of the array. so it is [int (*ptr)[5];] is a pointer to array not array pointer which can be declared by int *ptr[5];
#include<stdio.h>
int main()
{
int arr[5];
int (*ptr)[5];
ptr=&arr[10];
printf("%ld",ptr[5]);
return 0;
}
#include<stdio.h>
int main()
{
int arr[5];
int (*ptr)[5];
ptr=&arr[10];
printf("%ld",ptr[5]);
return 0;
}
Subaidha said:
2 decades ago
* means its represent as a pointer variable and here within a array bracket they give us 10 integers.
So that the ans is B.
So that the ans is B.
Balaji said:
2 decades ago
Can you explain me the concept?
Purna chandra said:
2 decades ago
Yes p is pointer of 10 integers.
Ganesh said:
1 decade ago
*ptr is a pointer and[10] is array declarations.
LOL said:
1 decade ago
The brackets are the key to this problem. Always read C declarations from right to left (backwards) and start will stuff inside brackets.
[] = array * = pointer
int *ptr [10] backwards is [10] ptr * int
so this is Array of 10 pointers to int
int (*ptr)[10] bracket first and backwards is * ptr [10] int
so this is pointer to an array of 10 integers
[] = array * = pointer
int *ptr [10] backwards is [10] ptr * int
so this is Array of 10 pointers to int
int (*ptr)[10] bracket first and backwards is * ptr [10] int
so this is pointer to an array of 10 integers
Chris said:
1 decade ago
#include<stdio.h>
int main()
{
int a=5;
printf("%d %d %d %d %d", a++, a--, ++a, --a, a);
return 0;
}
// Ans : 4 5 5 4 5
Can any one explain the above code please ?
int main()
{
int a=5;
printf("%d %d %d %d %d", a++, a--, ++a, --a, a);
return 0;
}
// Ans : 4 5 5 4 5
Can any one explain the above code please ?
Sagar Said said:
2 decades ago
Can you explain me the concept
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