C Programming - Arrays - Discussion

Could you please explain the question.

Could you please explain the question?

@Chris

The given output '4 5 5 4 5' is matches in Turbo C - 16 OS (DOS).


But, I tried in GCC, the details are as below:

Warnings:=

prog.c: In function 'main':
prog.c:5: warning: operation on 'a' may be undefined
prog.c:5: warning: operation on 'a' may be undefined
prog.c:5: warning: operation on 'a' may be undefined
prog.c:5: warning: operation on 'a' may be undefined

Output:=

4 5 5 5 5

Please can anyone explain with full details here. Thanks in advance.

*ptr is a pointer and [10] is array is array declaration.

Can you explain me the concept?

We can use a * sometimes to declare the array both are same that is way answer is b.

Here we have to see the priority () have highest priority.

So int (*ptr)[] read it as pointer to array of integers.

If () is not there then int *ptr[] start with [] and it means array of pointers of type integers.

ptr is a pointer,which is a type of int.ptr is an array.

pointer of array is declared as type (*p)[14]
array of pointers is declared as type *p[14]

int (*ptr)[10]
also we can write it as
int *ptr[10]

this line says that ptr is a pointer type variable which stores the address of first element of a 10 elements array list
as we know that array is continous memory type allocation.....