C Programming - Arrays - Discussion

No, according to me,

Consider the code to follow. The scanf does NOT YIELD the base address, and the sizeof operator definitely does not give the base address.

#include<stdio.h>

int main()
{
int arr[] = {12, 14, 15, 23, 45};
printf("%d\n", sizeof(arr));
printf("%d\n", &arr);
printf("%d\n", arr);
scanf(&arr);
printf("%d\n", *arr);

return 0;
}

I agree @Nirupam.

Answer should be only A.

It is work fine by replacing statement

scanf("%d", arr[i]); to scanf("%d", &arr[i]); in devc++

#include<stdio.h>

int main()
{
int size, i;
scanf("%d", &size);
int arr[size];
for(i=1; i<=size; i++)
{
scanf("%d", &arr[i]);
printf("p=%d\n", arr[i]);
}
return 0;
}

Output:
5
1
p=1
2
p=2
3
p=3
4
p=4
5
p=5

--------------------------------
Process exited after 10.07 seconds with return value 0.
Press any key to continue....

Well explained @Nirupam.

As of me the answer should be A only.

&a is a pointer to the array. It means it denotes the address of the first element of the array which is nothing but the BASE ADDRESS.

If we print the value of &a and &[0] in hex format, both the values are same.

E.g:

int a[3] = {0, 1, 2};
printf("%x %x", &a, &a[0]);

Then how can we say &a does not yield the base address of the array?

The same happens when an array is passed as an argument to printf() or scanf(). That means both the methods yield the base address of the given array.

The answer is correct, first understand the question which is DOES NOT YIELD (means not giving base address).

Hence the answer becomes C and D. Because A and B yields the base address of an array.

considering,
DOES NOT yield the base address.

The &a will always give the right numerical value.

The answer should include a and c;

Where does the idea that scanf will give the base address come from?

@Adi :-is there any difference between base address and address of first element in an array ?

I can't understand &a will point to base address then why option B is not in answer.

&a will give the base address.

@jasmin: base address and address of first element is same.