C Programming - Arrays - Discussion
Discussion Forum : Arrays - Point Out Correct Statements (Q.No. 1)
1.
Which of the following is correct way to define the function fun() in the below program?
#include<stdio.h>
int main()
{
int a[3][4];
fun(a);
return 0;
}
Answer: Option
Explanation:
void fun(int p[][4]){ } is the correct way to write the function fun(). while the others are considered only the function fun() is called by using call by reference.
Discussion:
14 comments Page 1 of 2.
Yogesh polawar said:
5 years ago
Option C is correct.
Vandan said:
5 years ago
It is said that when we use "*" in front of the formal parameters it is called function. It represents function is called by reference that means the change of the values of the variables is permanent.
Sourav said:
8 years ago
According to me, option C is correct.
Achorite said:
8 years ago
Option C should be the answer.
void fun(int (*p)[][4])
{
}
void fun(int (*p)[][4])
{
}
Dipika More said:
9 years ago
Option A is right and array always passed by reference by default.
Suraj said:
9 years ago
Here we are sending the base address of 'a'(2d-array). So it should be received by a pointer to 1d-array.
example:
char n[10][20];
input(n);
void input(char (*p)[20])
{
}
example:
char n[10][20];
input(n);
void input(char (*p)[20])
{
}
Harsha vardhan said:
9 years ago
Does fun() means calling any function?
Fizzz said:
9 years ago
The name of the array "a'' represents the base address. We should be receiving a pointer to a 2D array instead of the array itself.
Kelvin D said:
9 years ago
According to me, the answer should be option C.
Shreya said:
10 years ago
Here passing the address so we should use pointer. Then how first option is correct?
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