Discussion :: Lipid - Section 1 (Q.No.20)
How many ATPs are formed during complete oxidation of palmitate?
Answer: Option C
No answer description available for this question.
|Ganesh said: (Nov 10, 2013)|
|The complete oxidation of palmitate to gives 08 acetyl coa, 7FADH and 7NADPH so 96 ATP from acetyl coa,14 ATP from FADH and 21 ATP FROM NADPH But 2 ATP WAS CONSUMED.|
|Sf R. said: (Jul 20, 2014)|
|Palmitic acid (16-C).
- 7 FADH2 = 14 ATP.
-7 NADH = 21 ATP.
-8 Acetyl CoA = 96 ATP.
Total = 131.
2 ATPs by activation step.
Net ATP : 131-2 = 129 ATP.
|Quincy Godfrey said: (Dec 4, 2014)|
|This answer is not making sense to me? Can you please explain more detail?|
|KüBra said: (Jan 31, 2015)|
|What is B-oxidation?|
|Abdullah said: (Feb 7, 2015)|
|Where the consumption occur? This is not clear.|
|Celiwe said: (Oct 11, 2016)|
|When the question says a complete oxidation, that involves TCA cycle? I am confused, please help me.|
|Hayko said: (Nov 17, 2016)|
|B-oxidation is a very important part of fatty acid degradation which occurs in the mitochondrial matrix. It is the conversion of carnitate into acyl CoA which ultimately through a series of reactions produce acetyl CoA as well as Acyl CoA.|
|Feruza said: (Feb 13, 2017)|
|Each fadh2 generates 1, 5 ATP. NADH H generates 2. 5 ATP. The correct answer is 108-2 is 106. 2 atp used in activation.|
|Monalisha said: (May 6, 2017)|
It's 106 only.
|John said: (Nov 9, 2017)|
|You are right @Feruza.|
|Komolafe said: (Jan 30, 2019)|
|Palmitate has 16 carbons.
Acetyl coA=16/2 * 12ATP = 96ATP.
Number of rounds =7 i.e. no of carbon/2 -1.
2FADH * 7 = 14.
3NADH *7 = 21.
96+14+21=131 - no of ATP used up during activation of fatty acid by co ASH, 2 =129.
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