Discussion :: Lipid - Section 1 (Q.No.20)
| 20. | How many ATPs are formed during complete oxidation of palmitate? |
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Answer: Option C Explanation: No answer description available for this question.
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| Ganesh said: (Nov 10, 2013) | |
| The complete oxidation of palmitate to gives 08 acetyl coa, 7FADH and 7NADPH so 96 ATP from acetyl coa,14 ATP from FADH and 21 ATP FROM NADPH But 2 ATP WAS CONSUMED. | |
| Sf R. said: (Jul 20, 2014) | |
| Palmitic acid (16-C). 7 B-oxidation. - 7 FADH2 = 14 ATP. -7 NADH = 21 ATP. -8 Acetyl CoA = 96 ATP. Total = 131. 2 ATPs by activation step. Net ATP : 131-2 = 129 ATP. |
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| Quincy Godfrey said: (Dec 4, 2014) | |
| This answer is not making sense to me? Can you please explain more detail? | |
| KüBra said: (Jan 31, 2015) | |
| What is B-oxidation? | |
| Abdullah said: (Feb 7, 2015) | |
| Where the consumption occur? This is not clear. | |
| Celiwe said: (Oct 11, 2016) | |
| When the question says a complete oxidation, that involves TCA cycle? I am confused, please help me. | |
| Hayko said: (Nov 17, 2016) | |
| B-oxidation is a very important part of fatty acid degradation which occurs in the mitochondrial matrix. It is the conversion of carnitate into acyl CoA which ultimately through a series of reactions produce acetyl CoA as well as Acyl CoA. | |
| Feruza said: (Feb 13, 2017) | |
| Each fadh2 generates 1, 5 ATP. NADH H generates 2. 5 ATP. The correct answer is 108-2 is 106. 2 atp used in activation. | |
| Monalisha said: (May 6, 2017) | |
| Yes, @Feruza. It's 106 only. |
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| John said: (Nov 9, 2017) | |
| You are right @Feruza. | |
| Komolafe said: (Jan 30, 2019) | |
| Palmitate has 16 carbons. Acetyl coA=16/2 * 12ATP = 96ATP. Number of rounds =7 i.e. no of carbon/2 -1. 2FADH * 7 = 14. 3NADH *7 = 21. 96+14+21=131 - no of ATP used up during activation of fatty acid by co ASH, 2 =129. |
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