Biochemistry - Lipid - Discussion
Discussion Forum : Lipid - Section 1 (Q.No. 20)
20.
How many ATPs are formed during complete oxidation of palmitate?
Discussion:
11 comments Page 1 of 2.
Komolafe said:
7 years ago
Palmitate has 16 carbons.
Acetyl coA=16/2 * 12ATP = 96ATP.
Number of rounds =7 i.e. no of carbon/2 -1.
2FADH * 7 = 14.
3NADH *7 = 21.
96+14+21=131 - no of ATP used up during activation of fatty acid by co ASH, 2 =129.
Acetyl coA=16/2 * 12ATP = 96ATP.
Number of rounds =7 i.e. no of carbon/2 -1.
2FADH * 7 = 14.
3NADH *7 = 21.
96+14+21=131 - no of ATP used up during activation of fatty acid by co ASH, 2 =129.
John said:
8 years ago
You are right @Feruza.
Monalisha said:
8 years ago
Yes, @Feruza.
It's 106 only.
It's 106 only.
(1)
Feruza said:
9 years ago
Each fadh2 generates 1, 5 ATP. NADH H generates 2. 5 ATP. The correct answer is 108-2 is 106. 2 atp used in activation.
(1)
HAYKO said:
9 years ago
B-oxidation is a very important part of fatty acid degradation which occurs in the mitochondrial matrix. It is the conversion of carnitate into acyl CoA which ultimately through a series of reactions produce acetyl CoA as well as Acyl CoA.
Celiwe said:
9 years ago
When the question says a complete oxidation, that involves TCA cycle? I am confused, please help me.
Abdullah said:
1 decade ago
Where the consumption occur? This is not clear.
Kübra said:
1 decade ago
What is B-oxidation?
Quincy Godfrey said:
1 decade ago
This answer is not making sense to me? Can you please explain more detail?
SF R. said:
1 decade ago
Palmitic acid (16-C).
7 B-oxidation.
- 7 FADH2 = 14 ATP.
-7 NADH = 21 ATP.
-8 Acetyl CoA = 96 ATP.
Total = 131.
2 ATPs by activation step.
Net ATP : 131-2 = 129 ATP.
7 B-oxidation.
- 7 FADH2 = 14 ATP.
-7 NADH = 21 ATP.
-8 Acetyl CoA = 96 ATP.
Total = 131.
2 ATPs by activation step.
Net ATP : 131-2 = 129 ATP.
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