# Biochemistry - Lipid - Discussion

### Discussion :: Lipid - Section 1 (Q.No.20)

20.

How many ATPs are formed during complete oxidation of palmitate?

 [A]. 35 [B]. 96 [C]. 129 [D]. 131

Explanation:

No answer description available for this question.

 Ganesh said: (Nov 10, 2013) The complete oxidation of palmitate to gives 08 acetyl coa, 7FADH and 7NADPH so 96 ATP from acetyl coa,14 ATP from FADH and 21 ATP FROM NADPH But 2 ATP WAS CONSUMED.

 Sf R. said: (Jul 20, 2014) Palmitic acid (16-C). 7 B-oxidation. - 7 FADH2 = 14 ATP. -7 NADH = 21 ATP. -8 Acetyl CoA = 96 ATP. Total = 131. 2 ATPs by activation step. Net ATP : 131-2 = 129 ATP.

 Quincy Godfrey said: (Dec 4, 2014) This answer is not making sense to me? Can you please explain more detail?

 KüBra said: (Jan 31, 2015) What is B-oxidation?

 Abdullah said: (Feb 7, 2015) Where the consumption occur? This is not clear.

 Celiwe said: (Oct 11, 2016) When the question says a complete oxidation, that involves TCA cycle? I am confused, please help me.

 Hayko said: (Nov 17, 2016) B-oxidation is a very important part of fatty acid degradation which occurs in the mitochondrial matrix. It is the conversion of carnitate into acyl CoA which ultimately through a series of reactions produce acetyl CoA as well as Acyl CoA.

 Feruza said: (Feb 13, 2017) Each fadh2 generates 1, 5 ATP. NADH H generates 2. 5 ATP. The correct answer is 108-2 is 106. 2 atp used in activation.

 Monalisha said: (May 6, 2017) Yes, @Feruza. It's 106 only.

 John said: (Nov 9, 2017) You are right @Feruza.

 Komolafe said: (Jan 30, 2019) Palmitate has 16 carbons. Acetyl coA=16/2 * 12ATP = 96ATP. Number of rounds =7 i.e. no of carbon/2 -1. 2FADH * 7 = 14. 3NADH *7 = 21. 96+14+21=131 - no of ATP used up during activation of fatty acid by co ASH, 2 =129.