Biochemistry - Genetic Code and Regulation - Discussion
Discussion Forum : Genetic Code and Regulation - Section 1 (Q.No. 13)
13.
How many amino acids will be encoded by 5' GAU GGU UGA UGU 3' sequence?
Discussion:
7 comments Page 1 of 1.
Chisomo said:
6 years ago
UGA will stop the translation process therefore only producing two amino acids. To initiate mother start codon must be found.
Bas said:
7 years ago
3 amino acid will be encoded then why 2?
Khairullah said:
7 years ago
No, B is Right I agree @Alex.
Rita said:
8 years ago
How is it possible?
Correct answer is C because UGA is a stop codon.
Correct answer is C because UGA is a stop codon.
Alex said:
8 years ago
The answer is right UGA is a stop codon and terminates the chain and hence there are only two amino acids.
Nikhil said:
9 years ago
The answer is totally wrong.
GAU codes for aspartic acid.
GGU codes for glycine.
UGA codes for nothing its a stop codon.
UGU codes for cysteine.
GAU codes for aspartic acid.
GGU codes for glycine.
UGA codes for nothing its a stop codon.
UGU codes for cysteine.
Abdullah said:
1 decade ago
I am confuse about this. How this possible? Which codon act as start codon and how the 2 amino acid encoded? Can you explain?
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