Biochemical Engineering - Enzymes and Kinetics

Exercise : Enzymes and Kinetics - Section 2
6.
For an enzyme that displays Michaelis-Menten kinetics, the reaction velocity (as a fraction of Vmax) observed at [S] = 2 KM will be
0.09
0.33
0.66
0.91
Answer: Option
Explanation:
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7.
Predominantly uncompetitive inhibition may be called when
competitive inhibition is greater than uncompetitive inhibition
competitive inhibition is smaller than uncompetitive inhibition
competitive inhibition is equal to uncompetitive inhibition
none of the above
Answer: Option
Explanation:
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8.
An enzyme has a Km of 4.7 x 10-5M. If the Vmax of the preparation is 22m moles liter-1 min-1, what velocity would be observed in the presence of 2.0 x 10-4M substrate and 5.0 x 10-5M of a competitive inhibitor?
13.54μ moles liter-1min-1
6.68μ moles liter-1min-1
7.57μ moles liter-1min-1
17.8μ moles liter-1min-1
Answer: Option
Explanation:
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9.
The rate equation in non-competitive inhibition based on Michaelis Menten equation is given by
rmaxS/(Km + S)(1+I/Ki)
rmaxE/(Km (1+I/Ki)+S))
VmaxS/(Km + S)(1+I/Ki)
rmaxS/Km
Answer: Option
Explanation:
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10.
Which of the following statement(s) regarding enzymes, is/are false?
Enzymes are always proteins that function as catalysts
Enzymes provide activation energy for reactions
Enzyme activity can be regulated
Enzymes may be used many times for a specific reaction
Answer: Option
Explanation:
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