Aptitude - Volume and Surface Area - Discussion
Discussion Forum : Volume and Surface Area - General Questions (Q.No. 3)
3.
A hall is 15 m long and 12 m broad. If the sum of the areas of the floor and the ceiling is equal to the sum of the areas of four walls, the volume of the hall is:
Answer: Option
Explanation:
2(15 + 12) x h = 2(15 x 12)
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180 | m = | 20 | m. |
27 | 3 |
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15 x 12 x | 20 | ![]() |
= 1200 m3. |
3 |
Video Explanation: https://youtu.be/V8EQ1YIaH74
Discussion:
75 comments Page 3 of 8.
Avinash Kumar said:
8 years ago
To simplify it, we can separate the equation and calculate the surface area and ceiling area which is 2(15*12)=360 in total. Now as per question, it says that 4 walls have a total area of 360.
Now, we have to find the height of wall. So lets assume height is x.
So as per question, (15*x)+(12*x)+(15*x)+(12*x)=360. (Which is equal to floor + ceiling area)
if we will solve this equation, we will get the height of wall as 20/3.
Now we can find the are of hall by 20*15*20/3 which is equal to 1200.
Now, we have to find the height of wall. So lets assume height is x.
So as per question, (15*x)+(12*x)+(15*x)+(12*x)=360. (Which is equal to floor + ceiling area)
if we will solve this equation, we will get the height of wall as 20/3.
Now we can find the are of hall by 20*15*20/3 which is equal to 1200.
Sudhir said:
8 years ago
I didn't understand this! please explain it clearly.
Eaj said:
8 years ago
Thanks @Lokesh.
Ramesh said:
8 years ago
Thank for your explanation. @Sonu.
Geet said:
8 years ago
I cannot understand this! Please, anyone explain it.
Mapuia sailo said:
4 years ago
Why we using the cuboid formula? Please explain.
Ankur said:
8 years ago
Thank you for explaining the answer in well and suitable form @Lokesh.
Ann said:
8 years ago
@Erika,
Here four walls does not include the floor and the ceiling which is the top floor. Out of the four walls, sum of the areas of 2 walls which are opposite to each other is length* height+ length*height= 2*length*height.
Similarly, the sum of the areas of the 2 remaining two walls which are opposite to each other is breadth*height+breadth*height=2* breadth*height. So, the sum of areas of 4 walls= 2lh+2bh=2h (l+b). While calculating the area of a wall must consider the height of the wall.
Here four walls does not include the floor and the ceiling which is the top floor. Out of the four walls, sum of the areas of 2 walls which are opposite to each other is length* height+ length*height= 2*length*height.
Similarly, the sum of the areas of the 2 remaining two walls which are opposite to each other is breadth*height+breadth*height=2* breadth*height. So, the sum of areas of 4 walls= 2lh+2bh=2h (l+b). While calculating the area of a wall must consider the height of the wall.
Srinja333 said:
3 years ago
Thanks @Sonu.
Jagruti said:
7 years ago
Thanks. @Sonu.
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