Aptitude - Volume and Surface Area - Discussion
Discussion Forum : Volume and Surface Area - General Questions (Q.No. 3)
3.
A hall is 15 m long and 12 m broad. If the sum of the areas of the floor and the ceiling is equal to the sum of the areas of four walls, the volume of the hall is:
Answer: Option
Explanation:
2(15 + 12) x h = 2(15 x 12)
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180 | m = | 20 | m. |
27 | 3 |
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15 x 12 x | 20 | ![]() |
= 1200 m3. |
3 |
Video Explanation: https://youtu.be/V8EQ1YIaH74
Discussion:
74 comments Page 1 of 8.
Gopal said:
1 decade ago
I can not understand the meaning of cube in answer.
Shahid said:
1 decade ago
Here given that
Area of four walls = (area of the base )+(area of ceiling)
As per Surface area of a cuboid we have 2(l+b)*h
Area of base is (l*b)
So from these 2 formula e we get the equation explained in the answer section
Area of four walls = (area of the base )+(area of ceiling)
As per Surface area of a cuboid we have 2(l+b)*h
Area of base is (l*b)
So from these 2 formula e we get the equation explained in the answer section
Akanksha said:
1 decade ago
What is ceiling?
Yuri said:
1 decade ago
@ akansha ceiling means top wall, and hence its area is always equal to floor.
Ajith kumar said:
1 decade ago
Well not exactly. A ceiling is an overhead interior surface of a room that conceals the underside of the floor or roof structure above.
Reshma said:
1 decade ago
Hello all,
I could not understand the first step of the explanation.
According to this site surface area of cuboid is 2 (lb + bh + lh) sq. units.
I could not understand the first step of the explanation.
According to this site surface area of cuboid is 2 (lb + bh + lh) sq. units.
Yogarajan said:
1 decade ago
Hello, can any one clearly explain the basics of the concept please ?
Summi said:
1 decade ago
Hey can any one explain how you got 180/27cm ?
Geethu said:
1 decade ago
2(15*12)=2(lh+bh)
=2h(l+b)
15*12 = h(15+12)
h=(15*12)/(15+12)=180/27
=2h(l+b)
15*12 = h(15+12)
h=(15*12)/(15+12)=180/27
Sreelakshmi said:
1 decade ago
Please explain this concept with proper steps.
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