Aptitude - True Discount - Discussion
Discussion Forum : True Discount - General Questions (Q.No. 5)
5.
If Rs. 10 be allowed as true discount on a bill of Rs. 110 due at the end of a certain time, then the discount allowed on the same sum due at the end of double the time is:
Answer: Option
Explanation:
S.I. on Rs. (110 - 10) for a certain time = Rs. 10.
S.I. on Rs. 100 for double the time = Rs. 20.
T.D. on Rs. 120 = Rs. (120 - 100) = Rs. 20.
| T.D. on Rs. 110 = Rs. |  |
20 | x 110 |  |
= Rs. 18.33 |
| 120 |
Discussion:
29 comments Page 1 of 3.
Sudip Dhara said:
6 years ago
See, the true discount allowed is Rs. 10 and the amount to be paid after a certain time is Rs. 110.
We don't know the time and the present worth. So lets assume a value. Let's say the present worth is Rs.100, and the time is 1 year. Thus the Rate has to be 10%. Now double the time, so what is the present worth if Rs.110 was due in 2 years at 10%? It comes out to be Rs. 91.66. Thus the true discount becomes Rs.18.33.)
We don't know the time and the present worth. So lets assume a value. Let's say the present worth is Rs.100, and the time is 1 year. Thus the Rate has to be 10%. Now double the time, so what is the present worth if Rs.110 was due in 2 years at 10%? It comes out to be Rs. 91.66. Thus the true discount becomes Rs.18.33.)
(3)
Anvesh said:
10 years ago
Let suppose 110 should be paid after 1 year with a discount of Rs. 10.
-> Present worth (PW) = 110-10 = 100.
-> Rate = Discount*100/(PW*time) = 10.
The question is what will be the present worth, if the amount becomes 110 after 2 years with rate 10% per year.
-> Present worth = 110/(1+10*2/100) = 91.67.
-> Discount = 110-91.67 = 18.33.
-> Present worth (PW) = 110-10 = 100.
-> Rate = Discount*100/(PW*time) = 10.
The question is what will be the present worth, if the amount becomes 110 after 2 years with rate 10% per year.
-> Present worth = 110/(1+10*2/100) = 91.67.
-> Discount = 110-91.67 = 18.33.
Abhishek said:
1 decade ago
According to question,
Amount=110,True Discount=10,Present Worth=110-10=100;
Now,we know,P.W.=(Amount*100)/100+(R*T);
So,100=(110*100)/100+(R*T);that implies (R*T)=10;
Again in question,
(R*2T)=(2RT)=2*10=20;Now,
P.W.=(110*100)/100+(2RT)=(110*100)/100+20=91.66;
So,T.D.=Amount-P.W.=110-91.66=Rs.18.34/- (clear)....
Amount=110,True Discount=10,Present Worth=110-10=100;
Now,we know,P.W.=(Amount*100)/100+(R*T);
So,100=(110*100)/100+(R*T);that implies (R*T)=10;
Again in question,
(R*2T)=(2RT)=2*10=20;Now,
P.W.=(110*100)/100+(2RT)=(110*100)/100+20=91.66;
So,T.D.=Amount-P.W.=110-91.66=Rs.18.34/- (clear)....
(14)
Madhukumar E said:
1 decade ago
It's given that,
If, TD on 110 = 10 at certain time hence,
then, TD on 100 =20 at double the time hence,
110 = 20.
100 = ?
= 18.18.
In the same way.
If, TD on 120 = 20 at certain time hence,
then, TD on 110 = x.
120 = 20.
110 = ?
20/120 = 1/6.
1/6*110 = 18.33.
So 18.33 answer.
If, TD on 110 = 10 at certain time hence,
then, TD on 100 =20 at double the time hence,
110 = 20.
100 = ?
= 18.18.
In the same way.
If, TD on 120 = 20 at certain time hence,
then, TD on 110 = x.
120 = 20.
110 = ?
20/120 = 1/6.
1/6*110 = 18.33.
So 18.33 answer.
Mamta said:
10 years ago
PW = Amt*100/100+rt = td*100/rt.
=> 11000/100+rt = 1000/rt.
=> rt = 10.
Now, we have amt 110 on t double at are % and need to find out new TD on new PW or you can say.
TD = Amt - PW.
= 110 - 110*100/100+r*2t.
= 110(1-100/100+2*10).
= 110(1-100/120) = 18.33.
=> 11000/100+rt = 1000/rt.
=> rt = 10.
Now, we have amt 110 on t double at are % and need to find out new TD on new PW or you can say.
TD = Amt - PW.
= 110 - 110*100/100+r*2t.
= 110(1-100/100+2*10).
= 110(1-100/120) = 18.33.
(1)
Teja said:
4 years ago
In the question itself( T.R =10), they doubled the time that means then P.W also changes.
So, calculate the P.W after change by (2 .T.R=20).
A = P.W(1+2.T.R/100).
110 = P.W(1+20/100).
P.W = 110(5/6).
T.D = A - P.W = 110 - 110(5/6) = 110/6 = 18.33.
So, calculate the P.W after change by (2 .T.R=20).
A = P.W(1+2.T.R/100).
110 = P.W(1+20/100).
P.W = 110(5/6).
T.D = A - P.W = 110 - 110(5/6) = 110/6 = 18.33.
(3)
Aejaz said:
1 decade ago
This can be taken as principal as 100 and amount as 110 then from amount = p + PTR/100 then we get RT as 10 : Now 2RT =20
and Amount is 110 then find the principal from above formula we will get amount as 91.65 so the discount is 110-91.67=18.33
and Amount is 110 then find the principal from above formula we will get amount as 91.65 so the discount is 110-91.67=18.33
Keerthi said:
8 years ago
Given.
T.D = 10, AMOUNT = 110.
SO, BY USING THE FORMULA.
100*AMT/(100+RT)=100 * T.D/(RT),
WE KNOW THAT RT= 10,
Since the question asked to find out the T.D after double the time
RT=20,
So, by using the same above formula T.D=18.3333.
T.D = 10, AMOUNT = 110.
SO, BY USING THE FORMULA.
100*AMT/(100+RT)=100 * T.D/(RT),
WE KNOW THAT RT= 10,
Since the question asked to find out the T.D after double the time
RT=20,
So, by using the same above formula T.D=18.3333.
(1)
Vinay said:
1 decade ago
The discount allowed on the same sum 110 is double the time means 10 becomes 20%
So, 20% will come.
Therefore, principal amount is 100 for both the cases
(20x 110)/120= Rs. 18.33
So, 20% will come.
Therefore, principal amount is 100 for both the cases
(20x 110)/120= Rs. 18.33
Meha said:
1 decade ago
Whar ever the formula is given at biginig that was not comparable here. Which formula you are used here? please expline the formula.
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