Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 9)
9.
A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?
23 days
37 days
371/2
40 days
Answer: Option
Explanation:

Whole work is done by A in ( 20 x 5 ) = 25 days.
4

Now, ( 1 - 4 ) i.e., 1 work is done by A and B in 3 days.
5 5

Whole work will be done by A and B in (3 x 5) = 15 days.

A's 1 day's work = 1 , (A + B)'s 1 day's work = 1 .
25 15

Therefore B's 1 day's work = ( 1 - 1 ) = 4 = 2 .
15 25 150 75

So, B alone would do the work in 75 = 37 1 days.
2 2

Discussion:
164 comments Page 9 of 17.

Rahul Berry said:   9 years ago
Thank you for your valid explanation @Baskar.

Muna sharma said:   9 years ago
LCM of 15 and 25 is 150? Isn't it 75?

Muna sharma said:   9 years ago
How 80/100 can be 5/4? It should be 4/5.

Nagendran said:   9 years ago
Can anyone explain B's 1 day's work?

Jiya said:   9 years ago
Still, I'm not getting why its 5/4*20? Please explain briefly.

PrasadJadapalli said:   9 years ago
Super explanation @Snehagoud.

PrasadJadapalli said:   9 years ago
Super explanation @Snehagoud.

Satish said:   9 years ago
A - 20 - 80/100.
A - 1 - 80/(100 * 20) = 1/25.

A and B - 3 days = 20/100.
" 1 " = 20/(100 * 3).
= 1/15.
So,
1/15 -1/25 = 75/2.

Sky said:   9 years ago
Well explained, Thank you @Baskar.

Wilson said:   9 years ago
A's 1 day work = 80% / 20 days
= 80/20
= 4 ( 4% work per day done by 'A' )

Remaining, (100 - 80) 20% work done by 'A' and 'B' in 3 days.

It means 'A' must have done 4% work per day, So, in 3 Days = 4% * 3.
= 4 * 3.
= 12.(12%work done by 'A' out of 20%).

Now, 8% (20-12) work done by 'B' in 3 Days.
Therefore, 'B' Alone can do Work = 100/8 * 3.
= 37 1/2 days.


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