Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 9)
9.
A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?
Answer: Option
Explanation:
| Whole work is done by A in | ![]() |
20 x | 5 | ![]() |
= 25 days. |
| 4 |
| Now, | ![]() |
1 - | 4 | ![]() |
i.e., | 1 | work is done by A and B in 3 days. |
| 5 | 5 |
Whole work will be done by A and B in (3 x 5) = 15 days.
| A's 1 day's work = | 1 | , (A + B)'s 1 day's work = | 1 | . |
| 25 | 15 |
B's 1 day's work = |
![]() |
1 | - | 1 | ![]() |
= | 4 | = | 2 | . |
| 15 | 25 | 150 | 75 |
| So, B alone would do the work in | 75 | = 37 | 1 | days. |
| 2 | 2 |
Discussion:
165 comments Page 9 of 17.
Jyoti said:
9 years ago
A does 80% work means 80÷100 =4/5 work in 20 days.
So, A's 1 day work = 4/5 * 1/20 = 1/25 work in 1day.
Now, It is said that A+B can do a piece of work in 3 days.
Therefore remaining work =1 - 4/5 = 1/5.
So, A+B's 1day work = 1/5 * 1/3 = 1/15.
Now work done by B in 1 day = 1/15-1/25 = 2/75.
Therefore B can do whole work in 75/2.
Hope it is clear to you!
So, A's 1 day work = 4/5 * 1/20 = 1/25 work in 1day.
Now, It is said that A+B can do a piece of work in 3 days.
Therefore remaining work =1 - 4/5 = 1/5.
So, A+B's 1day work = 1/5 * 1/3 = 1/15.
Now work done by B in 1 day = 1/15-1/25 = 2/75.
Therefore B can do whole work in 75/2.
Hope it is clear to you!
Rahul Berry said:
9 years ago
Thank you for your valid explanation @Baskar.
Muna sharma said:
9 years ago
LCM of 15 and 25 is 150? Isn't it 75?
Muna sharma said:
9 years ago
How 80/100 can be 5/4? It should be 4/5.
Nagendran said:
9 years ago
Can anyone explain B's 1 day's work?
Jiya said:
9 years ago
Still, I'm not getting why its 5/4*20? Please explain briefly.
PrasadJadapalli said:
9 years ago
Super explanation @Snehagoud.
PrasadJadapalli said:
9 years ago
Super explanation @Snehagoud.
Satish said:
9 years ago
A - 20 - 80/100.
A - 1 - 80/(100 * 20) = 1/25.
A and B - 3 days = 20/100.
" 1 " = 20/(100 * 3).
= 1/15.
So,
1/15 -1/25 = 75/2.
A - 1 - 80/(100 * 20) = 1/25.
A and B - 3 days = 20/100.
" 1 " = 20/(100 * 3).
= 1/15.
So,
1/15 -1/25 = 75/2.
Sky said:
9 years ago
Well explained, Thank you @Baskar.
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B's 1 day's work =