Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 9)
9.
A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?
23 days
37 days
371/2
40 days
Answer: Option
Explanation:

Whole work is done by A in ( 20 x 5 ) = 25 days.
4

Now, ( 1 - 4 ) i.e., 1 work is done by A and B in 3 days.
5 5

Whole work will be done by A and B in (3 x 5) = 15 days.

A's 1 day's work = 1 , (A + B)'s 1 day's work = 1 .
25 15

Therefore B's 1 day's work = ( 1 - 1 ) = 4 = 2 .
15 25 150 75

So, B alone would do the work in 75 = 37 1 days.
2 2

Discussion:
164 comments Page 3 of 17.

Logesh said:   1 year ago
Good, Thanks @Keerthan G.
(5)

Sai Ram said:   4 years ago
Here the answer in simple steps:

A 's work in 20 days = 80/100 = 4/5

Then, A's 1 day work is = 4/5*20 =4/100=1/25.

(Here we simply multiply the 20 in the denominator)

So,

A+B 's 3 days work = 1/5
A+B's 1 day work = 1/5 * 3 = 1/15.

(Here the 1/5 comes as, in Factional total work is 1 so when we subtract the A s 4/5 from 1 we get the remaining work which is going to complete by A and B is 1/5).

So we got A's work and A+B 's work when we subtract the both we got B's time to complete it
1/15-1/25 = 2/75 it is an efficiency when you reciprocal it, we got 75/3 that is in 35.5 or 35 1/2 days.
(4)

Joy khwaka said:   3 years ago
Finally, I understood the concept, Thanks @Rajendra.
(4)

Jeevesh said:   2 years ago
@Rajendra.

Thank you for explaining.
(4)

Kasi Viswesh said:   2 years ago
This can also be solved in this way.
A - 80% work in 20 days .
=>1/A=1/20 (1 day work of A) ---> 1

Also Given remaining 20% work done in 3 days by help of B.
Let us calculate days if they work for other 80%.

20% = 3 days.
80% = x.
x = 12 days.
=> 1/A + 1/B = 1/12.

Substitute value of 1/A from eq 1
then B = 30

=> 80% = 30 days,
100% = x.
By calculating x = 37.5.
So, B alone can finish work in 37.5 days.
(3)

SIVARANJANI said:   1 decade ago
Sorry I can't get it why we should multiply with that 5/4 ?
(2)

Rajendra said:   1 decade ago
A does 80% in 20 days..so
A does 100% in 25 days..
A's 1 day work=1/25
A+B does 20% in 3 days..so
A+B does 100% in 15 days
A+B's 1 day work=1/15
1/25+B=1/15
B=1/15-1/25
B,s 1 day work=2/75
so B,s work=75/2 i.e 37 1/2 days..
(2)

Navraj Bhatta said:   4 years ago
A finish 80% work in 20 days.
A finish 100% work in 20/80*100 = 25 days,
A+B finish the remaining 20% of work in 3 days,
A+B finish 100% work in 3/20*100 = 15 days.

Now A finishes the whole work in 25 days and A+B finishes the same work in 25 days.
Now total work is LCM of 15 and 25 =75

A's work of one day =75/25 = 3.
A+B work of one day=75/15 = 5.
B's work of one day= (A+B)-A = 2 - 3 = 2.

Now the time is taken by B to complete the whole work= total work/B's per day work =75/2 = 37.5.
(2)

Kajal said:   3 years ago
@Baskar.

Thank you very much for your explanation.
(2)

Jay said:   1 decade ago
@shefali..the 15 days is nothing but remaining work probability. 4/5 i.e 80% work is done by A so remaining is 1-(4/5)= 1/5. its same like p+q=1 in probability.
n same like 3*5=15 days
(1)


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