Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 9)
9.
A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?
Answer: Option
Explanation:
| Whole work is done by A in | ![]() |
20 x | 5 | ![]() |
= 25 days. |
| 4 |
| Now, | ![]() |
1 - | 4 | ![]() |
i.e., | 1 | work is done by A and B in 3 days. |
| 5 | 5 |
Whole work will be done by A and B in (3 x 5) = 15 days.
| A's 1 day's work = | 1 | , (A + B)'s 1 day's work = | 1 | . |
| 25 | 15 |
B's 1 day's work = |
![]() |
1 | - | 1 | ![]() |
= | 4 | = | 2 | . |
| 15 | 25 | 150 | 75 |
| So, B alone would do the work in | 75 | = 37 | 1 | days. |
| 2 | 2 |
Discussion:
164 comments Page 3 of 17.
Logesh said:
1 year ago
Good, Thanks @Keerthan G.
(5)
Sai Ram said:
4 years ago
Here the answer in simple steps:
A 's work in 20 days = 80/100 = 4/5
Then, A's 1 day work is = 4/5*20 =4/100=1/25.
(Here we simply multiply the 20 in the denominator)
So,
A+B 's 3 days work = 1/5
A+B's 1 day work = 1/5 * 3 = 1/15.
(Here the 1/5 comes as, in Factional total work is 1 so when we subtract the A s 4/5 from 1 we get the remaining work which is going to complete by A and B is 1/5).
So we got A's work and A+B 's work when we subtract the both we got B's time to complete it
1/15-1/25 = 2/75 it is an efficiency when you reciprocal it, we got 75/3 that is in 35.5 or 35 1/2 days.
A 's work in 20 days = 80/100 = 4/5
Then, A's 1 day work is = 4/5*20 =4/100=1/25.
(Here we simply multiply the 20 in the denominator)
So,
A+B 's 3 days work = 1/5
A+B's 1 day work = 1/5 * 3 = 1/15.
(Here the 1/5 comes as, in Factional total work is 1 so when we subtract the A s 4/5 from 1 we get the remaining work which is going to complete by A and B is 1/5).
So we got A's work and A+B 's work when we subtract the both we got B's time to complete it
1/15-1/25 = 2/75 it is an efficiency when you reciprocal it, we got 75/3 that is in 35.5 or 35 1/2 days.
(4)
Joy khwaka said:
3 years ago
Finally, I understood the concept, Thanks @Rajendra.
(4)
Jeevesh said:
2 years ago
@Rajendra.
Thank you for explaining.
Thank you for explaining.
(4)
Kasi Viswesh said:
2 years ago
This can also be solved in this way.
A - 80% work in 20 days .
=>1/A=1/20 (1 day work of A) ---> 1
Also Given remaining 20% work done in 3 days by help of B.
Let us calculate days if they work for other 80%.
20% = 3 days.
80% = x.
x = 12 days.
=> 1/A + 1/B = 1/12.
Substitute value of 1/A from eq 1
then B = 30
=> 80% = 30 days,
100% = x.
By calculating x = 37.5.
So, B alone can finish work in 37.5 days.
A - 80% work in 20 days .
=>1/A=1/20 (1 day work of A) ---> 1
Also Given remaining 20% work done in 3 days by help of B.
Let us calculate days if they work for other 80%.
20% = 3 days.
80% = x.
x = 12 days.
=> 1/A + 1/B = 1/12.
Substitute value of 1/A from eq 1
then B = 30
=> 80% = 30 days,
100% = x.
By calculating x = 37.5.
So, B alone can finish work in 37.5 days.
(3)
SIVARANJANI said:
1 decade ago
Sorry I can't get it why we should multiply with that 5/4 ?
(2)
Rajendra said:
1 decade ago
A does 80% in 20 days..so
A does 100% in 25 days..
A's 1 day work=1/25
A+B does 20% in 3 days..so
A+B does 100% in 15 days
A+B's 1 day work=1/15
1/25+B=1/15
B=1/15-1/25
B,s 1 day work=2/75
so B,s work=75/2 i.e 37 1/2 days..
A does 100% in 25 days..
A's 1 day work=1/25
A+B does 20% in 3 days..so
A+B does 100% in 15 days
A+B's 1 day work=1/15
1/25+B=1/15
B=1/15-1/25
B,s 1 day work=2/75
so B,s work=75/2 i.e 37 1/2 days..
(2)
Navraj Bhatta said:
4 years ago
A finish 80% work in 20 days.
A finish 100% work in 20/80*100 = 25 days,
A+B finish the remaining 20% of work in 3 days,
A+B finish 100% work in 3/20*100 = 15 days.
Now A finishes the whole work in 25 days and A+B finishes the same work in 25 days.
Now total work is LCM of 15 and 25 =75
A's work of one day =75/25 = 3.
A+B work of one day=75/15 = 5.
B's work of one day= (A+B)-A = 2 - 3 = 2.
Now the time is taken by B to complete the whole work= total work/B's per day work =75/2 = 37.5.
A finish 100% work in 20/80*100 = 25 days,
A+B finish the remaining 20% of work in 3 days,
A+B finish 100% work in 3/20*100 = 15 days.
Now A finishes the whole work in 25 days and A+B finishes the same work in 25 days.
Now total work is LCM of 15 and 25 =75
A's work of one day =75/25 = 3.
A+B work of one day=75/15 = 5.
B's work of one day= (A+B)-A = 2 - 3 = 2.
Now the time is taken by B to complete the whole work= total work/B's per day work =75/2 = 37.5.
(2)
Kajal said:
3 years ago
@Baskar.
Thank you very much for your explanation.
Thank you very much for your explanation.
(2)
Jay said:
1 decade ago
@shefali..the 15 days is nothing but remaining work probability. 4/5 i.e 80% work is done by A so remaining is 1-(4/5)= 1/5. its same like p+q=1 in probability.
n same like 3*5=15 days
n same like 3*5=15 days
(1)
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B's 1 day's work =