Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 9)
9.
A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?
23 days
37 days
371/2
40 days
Answer: Option
Explanation:

Whole work is done by A in ( 20 x 5 ) = 25 days.
4

Now, ( 1 - 4 ) i.e., 1 work is done by A and B in 3 days.
5 5

Whole work will be done by A and B in (3 x 5) = 15 days.

A's 1 day's work = 1 , (A + B)'s 1 day's work = 1 .
25 15

Therefore B's 1 day's work = ( 1 - 1 ) = 4 = 2 .
15 25 150 75

So, B alone would do the work in 75 = 37 1 days.
2 2

Discussion:
164 comments Page 14 of 17.

Nani said:   8 years ago
Good explanation, thank you @Rajendra.

Muna sharma said:   9 years ago
LCM of 15 and 25 is 150? Isn't it 75?

Reya said:   7 years ago
(1/15) - (1/25) how to simplify this?

Jeevesh said:   2 years ago
@Rajendra.

Thank you for explaining.
(4)

Nazeem said:   1 decade ago
Great explanation by baskar. Thanks.

Himanshu gawande said:   1 decade ago
A's 1 day work (1/80%)x20 = 25 days.

Nagendran said:   9 years ago
Can anyone explain B's 1 day's work?

Kannan said:   10 years ago
I don't understand please explain.

Sweety said:   8 years ago
Thanks for the explanation @Baskar.

Sky said:   9 years ago
Well explained, Thank you @Baskar.


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