Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 9)
9.
A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?
23 days
37 days
371/2
40 days
Answer: Option
Explanation:

Whole work is done by A in ( 20 x 5 ) = 25 days.
4

Now, ( 1 - 4 ) i.e., 1 work is done by A and B in 3 days.
5 5

Whole work will be done by A and B in (3 x 5) = 15 days.

A's 1 day's work = 1 , (A + B)'s 1 day's work = 1 .
25 15

Therefore B's 1 day's work = ( 1 - 1 ) = 4 = 2 .
15 25 150 75

So, B alone would do the work in 75 = 37 1 days.
2 2

Discussion:
164 comments Page 11 of 17.

Swapraj said:   8 years ago
80%= 4/5.

But, work done by A = 5/4 * 20 why not 4/5 * 20.

Please explain me.

Mathi said:   1 decade ago
A = (1/20) * (80/100) = 1/25
1/A + 1/B =1/3(20/100)
1/B=(1/15) - (1/25) =2/75
(1)

Charu said:   1 decade ago
Thanks Bhasker, Ganesh and Mini... Keep up the good work!!! cheers

Kriti said:   9 years ago
Hey guys 80/100 = 4/5 then why you people multiplying 5/4 * 20?

Prathap said:   1 decade ago
Bhaskar and rajendra you both are explained very well. Thanks.

Jiya said:   9 years ago
Still, I'm not getting why its 5/4*20? Please explain briefly.

Shefali said:   1 decade ago
How do we get that A & B together can do work in 15 days?

SIVARANJANI said:   1 decade ago
Sorry I can't get it why we should multiply with that 5/4 ?
(2)

Vinoth said:   1 decade ago
@baskar your explations were very nice thank you so much.

Zaidi said:   7 years ago
@Reya.

Take L.C.M of 15 and 25 which comes out to be 75.


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