Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 13)
13.
A and B can together finish a work 30 days. They worked together for 20 days and then B left. After another 20 days, A finished the remaining work. In how many days A alone can finish the work?
Answer: Option
Explanation:
| (A + B)'s 20 day's work = |  |
1 | x 20 |  |
= | 2 | . |
| 30 | 3 |
| Remaining work = | |
1 - | 2 | |
= | 1 | . |
| 3 | 3 |
| Now, | 1 | work is done by A in 20 days. |
| 3 |
Therefore, the whole work will be done by A in (20 x 3) = 60 days.
Discussion:
64 comments Page 7 of 7.
Soumya said:
9 years ago
Pushpa can do a work in 10 days and Komal can do in 20 days. They work together for 5 days, then komal goes away In how many days more will Pushpa finish the work?
Can anyone solve this?
Can anyone solve this?
Arya said:
9 years ago
A + B = 1/30 its entire work But
A + B work together only for 20 days so...
A + B - A
1/30 - 1/20
LCM is 60.
So, 2 - 3 ÷60.
1/60 = 60 Days.
A + B work together only for 20 days so...
A + B - A
1/30 - 1/20
LCM is 60.
So, 2 - 3 ÷60.
1/60 = 60 Days.
Poorvi said:
9 years ago
Pushpas work 1/10.
Komals work. 1/20 Per day.
So, they work for 5 days.
Their total work should be calculated by 1/10 + 1/20 then -1/5 you'll get the Answer.
Hope it's correct.
Komals work. 1/20 Per day.
So, they work for 5 days.
Their total work should be calculated by 1/10 + 1/20 then -1/5 you'll get the Answer.
Hope it's correct.
Poorvi said:
9 years ago
Good explanations. Thank you all.
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