Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 1)
1.
A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :
Answer: Option
Explanation:
| A's 1 day's work = | 1 | ; |
| 15 |
| B's 1 day's work = | 1 | ; |
| 20 |
| (A + B)'s 1 day's work = |  |
1 | + | 1 |  |
= | 7 | . |
| 15 | 20 | 60 |
| (A + B)'s 4 day's work = | |
7 | x 4 | |
= | 7 | . |
| 60 | 15 |
| Therefore, Remaining work = | |
1 - | 7 | |
= | 8 | . |
| 15 | 15 |
Discussion:
355 comments Page 36 of 36.
SAKSHI said:
5 months ago
Yes, It is 8/15.
(7)
Malik shahnawaz said:
4 months ago
W(A) = eff * time = 4 * 4 = 16
W(B) = rff * time = 3 * 4 = 12.
Total work in 4 days = 28.
Remaining work = 60 - 28 = 32.
Fraction of work left = 32/60 = 8/15.
W(B) = rff * time = 3 * 4 = 12.
Total work in 4 days = 28.
Remaining work = 60 - 28 = 32.
Fraction of work left = 32/60 = 8/15.
(30)
Renuka karki said:
2 months ago
Yes, agree 8/15 is the answer.
(5)
Ambika said:
2 months ago
A ---> 15 days.
B ---> 20 days.
LCM --> 60.
A--> efficiency 4.
B--> efficiency 3.
Total 4 days work = 4 * 7 = 28.
Remaining work = 60 - 28 = 32.
32/60 = 8/15.
B ---> 20 days.
LCM --> 60.
A--> efficiency 4.
B--> efficiency 3.
Total 4 days work = 4 * 7 = 28.
Remaining work = 60 - 28 = 32.
32/60 = 8/15.
(29)
A K BURNWAL said:
1 month ago
A's work = 15,
b's work = 20,
LCM - 60.
Efficiency of a -4, b - 3.
a's 4 day work = 4 * 4 = 16.
b's 4 day work= 4 * 3 = 12.
Total work remain = 60 - (16 + 12) = 32.
work left = 32/60 = 8/15.
b's work = 20,
LCM - 60.
Efficiency of a -4, b - 3.
a's 4 day work = 4 * 4 = 16.
b's 4 day work= 4 * 3 = 12.
Total work remain = 60 - (16 + 12) = 32.
work left = 32/60 = 8/15.
(9)
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