Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 1)
1.
A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :
Answer: Option
Explanation:
A's 1 day's work = | 1 | ; |
15 |
B's 1 day's work = | 1 | ; |
20 |
(A + B)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 7 | . |
15 | 20 | 60 |
(A + B)'s 4 day's work = | ![]() |
7 | x 4 | ![]() |
= | 7 | . |
60 | 15 |
Therefore, Remaining work = | ![]() |
1 - | 7 | ![]() |
= | 8 | . |
15 | 15 |
Discussion:
344 comments Page 31 of 35.
Swetha said:
3 years ago
First of all, thank you to explain the method.
I have a doubt that how we know to take (i.e Total work = 60)?
Anyone, please help me to get it.
I have a doubt that how we know to take (i.e Total work = 60)?
Anyone, please help me to get it.
(6)
VisHnu RaM said:
3 years ago
Thank you for giving the clear explanation @Swetha.
And 60 will come, No of days LCM
15 days to 15 * 4 = 60.
20 days to 20 * 3 = 60.
So, the LCM is 60.
And 60 will come, No of days LCM
15 days to 15 * 4 = 60.
20 days to 20 * 3 = 60.
So, the LCM is 60.
(13)
Dibyanshu said:
3 years ago
A - 15 days.
B - 20 days.
LCM of 15 & 20 is 60 (The total work is 60 also).
So,
The Efficiency of one day's work is 60/15 = 4 and 60/20 = 3.
Then, both A & B can complete the work in one day is 4+3=7.
They worked for 4 days, so 7x4=28
Work completed in 4days by both A+B=28.
Then, rest work = Total work - Completed work
Rest work = 60-28=32.
32/60 = 8/15
The answer is = 8/15.
B - 20 days.
LCM of 15 & 20 is 60 (The total work is 60 also).
So,
The Efficiency of one day's work is 60/15 = 4 and 60/20 = 3.
Then, both A & B can complete the work in one day is 4+3=7.
They worked for 4 days, so 7x4=28
Work completed in 4days by both A+B=28.
Then, rest work = Total work - Completed work
Rest work = 60-28=32.
32/60 = 8/15
The answer is = 8/15.
(233)
Ayansh said:
3 years ago
How (1/15+1/20) = 7/60? Please explain me.
(37)
Radhika said:
3 years ago
@All.
As 1 is the whole work, so when we subtract 7/15 from 1.
Then,
LCM of 1 and 15 will be 15 ( in 1 the denominator will be 1 ).
So, 15-7/15 is 8/15.
As 1 is the whole work, so when we subtract 7/15 from 1.
Then,
LCM of 1 and 15 will be 15 ( in 1 the denominator will be 1 ).
So, 15-7/15 is 8/15.
(18)
Vinitha said:
2 years ago
@all
(1/15+1/20) =7/60.
Solution:
We have to use the mixed fraction method in a simple way using cross multiplication so it becomes (15+20)/300.
The reason for the 300 came we use the denominator direct multiplication (15*20=300)
Then 15+20 = 35,
Divide:35/300.
It becomes 7/60.
(1/15+1/20) =7/60.
Solution:
We have to use the mixed fraction method in a simple way using cross multiplication so it becomes (15+20)/300.
The reason for the 300 came we use the denominator direct multiplication (15*20=300)
Then 15+20 = 35,
Divide:35/300.
It becomes 7/60.
(38)
Sankalp said:
2 years ago
Please explain, why the remaining work is 1.
(60)
RichardAnthony said:
2 years ago
Just take LCM of 15 and 20 you will get total work of 60.
(17)
Vicky Kumar said:
2 years ago
A completed this in 15 days.
Then, A completed this work in 1 days = (1/15).
B completed this work in 20 days
Then, B completed this work in 1 days = (1/20).
Both A and B both completed this work in 1 days = (A+B)
= ((1/15)+(1/20)).
then, the LCM of 15 and 20 is 60;
we get,
((1*4)+(1*3)/60))
= 7/60.
A and B both completed the same work in 4 days = ((7/60)*4)
= 7/15.
Let's take total work is = 1.
then we know that,
Rest work= total work - completed work.
= 1 - (7/15).
= (15-7)/15.
= 8/15 Answer.
Then, A completed this work in 1 days = (1/15).
B completed this work in 20 days
Then, B completed this work in 1 days = (1/20).
Both A and B both completed this work in 1 days = (A+B)
= ((1/15)+(1/20)).
then, the LCM of 15 and 20 is 60;
we get,
((1*4)+(1*3)/60))
= 7/60.
A and B both completed the same work in 4 days = ((7/60)*4)
= 7/15.
Let's take total work is = 1.
then we know that,
Rest work= total work - completed work.
= 1 - (7/15).
= (15-7)/15.
= 8/15 Answer.
(81)
Sandeep said:
2 years ago
A's 1 day's work = 1/15;
B's 1 day's work = 1/20;
(A + B)'s 1 day's work = (1/15+1/20)= 7/60;
Total days required to complete total work of (A+B) = 60/7,
After 4 days, remaining days left = 60/7 - 4 = 32/7,
Hence, remaining work = 32/7 x 7/60 = 8/15,
Hope it helps.
B's 1 day's work = 1/20;
(A + B)'s 1 day's work = (1/15+1/20)= 7/60;
Total days required to complete total work of (A+B) = 60/7,
After 4 days, remaining days left = 60/7 - 4 = 32/7,
Hence, remaining work = 32/7 x 7/60 = 8/15,
Hope it helps.
(63)
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