Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 1)
1.
A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :

1
4

1
10

7
15

8
15

Answer: Option
Explanation:

A's 1 day's work = 1 ;
15

B's 1 day's work = 1 ;
20

(A + B)'s 1 day's work = ( 1 + 1 ) = 7 .
15 20 60

(A + B)'s 4 day's work = ( 7 x 4 ) = 7 .
60 15

Therefore, Remaining work = ( 1 - 7 ) = 8 .
15 15

Discussion:
344 comments Page 3 of 35.

Dinesh kumar said:   2 years ago
A = 1/15
B = 1/20
(A+B) = 1/15+1/20 = 7/15
The remaining work = 1-7/15 = 8/15.
(26)

NADIPUDI SIRISHA said:   2 years ago
Thank you for explaining the answer @Giri.
(26)

Anonym said:   1 year ago
A, completes the work in 15 days so, the work done by A in 1 day = 1/15.

Similarly, B completes the work in 20 days therefore work done by B in 1 day = 1/20.

A and b work together = 1/15+1/20 i.e. => 14/120 => 7/60.
Now, they both worked for 4 days which will be = 4*7/60 => 7/15.

Let's suppose the total work is x and they have already worked for 4 days.
Therefore remaining work is x -7/15 (for more clarity take x-7/15 = 0) => 8/15.
(25)

Nitika said:   1 year ago
The reason why we've subtract from 1:

1 represents the whole work or complete work total work considered as 1(or 100%)
(23)

Bha said:   12 months ago
Thanks all for explaining the answer.
(23)

Raghu said:   1 year ago
How 7 comes? Please explain.
(22)

Jeevanantham M said:   2 years ago
@Ayansh.

For this;

(A+B) 's work rate = 1/15 + 1/20 = (4/60 + 3/60) = 7/60.
(21)

Sowmiya said:   1 year ago
How remaing work =1? Please explain to me.
(20)

Radhika said:   3 years ago
@All.

As 1 is the whole work, so when we subtract 7/15 from 1.
Then,
LCM of 1 and 15 will be 15 ( in 1 the denominator will be 1 ).
So, 15-7/15 is 8/15.
(18)

RichardAnthony said:   2 years ago
Just take LCM of 15 and 20 you will get total work of 60.
(17)


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