Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 1)
1.
A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :
Answer: Option
Explanation:
A's 1 day's work = | 1 | ; |
15 |
B's 1 day's work = | 1 | ; |
20 |
(A + B)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 7 | . |
15 | 20 | 60 |
(A + B)'s 4 day's work = | ![]() |
7 | x 4 | ![]() |
= | 7 | . |
60 | 15 |
Therefore, Remaining work = | ![]() |
1 - | 7 | ![]() |
= | 8 | . |
15 | 15 |
Discussion:
344 comments Page 29 of 35.
Billal Hossin said:
5 years ago
@All.
According to me, it can be solve by 2 methods.
Method- 1:
A's 1 day work = 1/15.
B's 1 day work= 1/40.
(A+B)'s 1 day work= (1/15)+(1/40).
= (8+6) /120.
= 14/120.
= 7/60,
(A+B)'s 4 days work= (7*4)/600,
= 7/15,
Left work is= 1- (7/15 ),
= 8/15 (Ans).
Method-2:
(A+B)'s 4 days work= (4/15)+(4/20),
= (4/15)+(1/5),
= 7/15.
Left work= 1- (7/15).
= 8/15 (Ans).
According to me, it can be solve by 2 methods.
Method- 1:
A's 1 day work = 1/15.
B's 1 day work= 1/40.
(A+B)'s 1 day work= (1/15)+(1/40).
= (8+6) /120.
= 14/120.
= 7/60,
(A+B)'s 4 days work= (7*4)/600,
= 7/15,
Left work is= 1- (7/15 ),
= 8/15 (Ans).
Method-2:
(A+B)'s 4 days work= (4/15)+(4/20),
= (4/15)+(1/5),
= 7/15.
Left work= 1- (7/15).
= 8/15 (Ans).
Vishnu said:
5 years ago
Good, thanks @Billal Hossin.
Kundan said:
5 years ago
A one day work = 1/15.
B one day work = 1/20.
One day work of both = 1/15 + 1/20 = 7/60.
4days work of both = 7/60 * 4 = 7/15 is the total work of 4days.
So, remaining days work = 1 - 7/15 = 8/15.
Hence, 8/15 answer.
B one day work = 1/20.
One day work of both = 1/15 + 1/20 = 7/60.
4days work of both = 7/60 * 4 = 7/15 is the total work of 4days.
So, remaining days work = 1 - 7/15 = 8/15.
Hence, 8/15 answer.
Yeswanth said:
5 years ago
A's 1 day's work =1/15.
B's 1 day's work =1/20.
(A + B)'s 1 day's work = (1/15 + 1/20) = 7/60.
(A + B)'s 4 day's work = 4 * (7/60) = 28/60.
In 4 days they complete 28 parts of work out of 60 parts of work.
Rest of work is 32 parts.
:=> 32/60 has to be completed i.e 8/15.
B's 1 day's work =1/20.
(A + B)'s 1 day's work = (1/15 + 1/20) = 7/60.
(A + B)'s 4 day's work = 4 * (7/60) = 28/60.
In 4 days they complete 28 parts of work out of 60 parts of work.
Rest of work is 32 parts.
:=> 32/60 has to be completed i.e 8/15.
Surya said:
5 years ago
(1/15+1/20).
Fractions of 15 and 20 are written as;
3*5 and 2'2 *5. = 60,
and 35 go for 7,
= 7/60.
Fractions of 15 and 20 are written as;
3*5 and 2'2 *5. = 60,
and 35 go for 7,
= 7/60.
Lohith said:
5 years ago
How (1/15+1/20 )= 7/60? Explain, please.
SR Ranees said:
5 years ago
Explination for (1/15 + 1/20) = 7/60,
take LCM of 15 and 20.
LCM will be 60,
= (1*4/15*4) + (1*3/20*3),
= (4+3)/60,
= 7/60.
take LCM of 15 and 20.
LCM will be 60,
= (1*4/15*4) + (1*3/20*3),
= (4+3)/60,
= 7/60.
MEGA MATH said:
4 years ago
1/15 + 1/20 = 7/60,
7/60*4 = 28/60,
If we simplify 28/60 by 4, then it is 8/15.
7/60*4 = 28/60,
If we simplify 28/60 by 4, then it is 8/15.
Asha Shetty said:
4 years ago
@Mega math.
I can't understand how t simplify 28/60 by 4 and how it becomes 8/15?
I can't understand how t simplify 28/60 by 4 and how it becomes 8/15?
Palak said:
4 years ago
Thanks all.
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