Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 1)
1.
A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :

1
4

1
10

7
15

8
15

Answer: Option
Explanation:

A's 1 day's work = 1 ;
15

B's 1 day's work = 1 ;
20

(A + B)'s 1 day's work = ( 1 + 1 ) = 7 .
15 20 60

(A + B)'s 4 day's work = ( 7 x 4 ) = 7 .
60 15

Therefore, Remaining work = ( 1 - 7 ) = 8 .
15 15

Discussion:
344 comments Page 14 of 35.

Sid said:   1 decade ago
LCM 15, 20 will give you 60 (the total work).

LCM of 15 and 20,

5*3 = 15.
5*4 = 20.

THEREFORE, 3*4*5 = 60.

1 day work of A = 60/15 = 4.
1 day work of B = 60/20 = 3.

1 day work of A and B together = 4 + 3 = 7 / 60.

A and B worked together for 4 days = 4 * 7/60 = 28/60 = 7 / 15.

Therefore,

Work left = Total work - Work done in 4 days by A and B together.

Work left (IN FRACTIONS) = 1 - 7/15 = (15-7)/15 = 8/15.

Thank you for giving me an opportunity.

L raj Scope said:   1 decade ago
How to come [1/15+1/20] = 7/60?

Prasanth.sunny143 said:   1 decade ago
@L Raj Scope

Please understand this concept first.

LET CONSIDER A SIMPLE STATEMENT:

A can do a work in 2 days.

That means A's 1 day work = 1/2.

This is the methodology we wanna apply on the data which is given in question.

From the question.

A (CAN D0 A JOB) ----15 days.
B (CAN DO A JOB) ----20 days.

Therefore by the above concept A's 1 day work = 1/15.

B's 1 day work = 1/20.

Therefore both A&B 1 work = (1/15)+1/20) = 7/60.

NOW READ THE QUESTION.

If A&B work together for 4 days then what the fraction of work left.

Consider:

Total work = 1.

A&B (4 DAYS WORK) = (7/60)*4 = 7/15.

REMAIN B WORK = (TOTAL WORK)-(COMPLETED WORK BY A&B FOR 4 DAYS).

= 1-7/15.

= 8/15.

Hope this is helpful.
(3)

Aravind said:   1 decade ago
Why calculate the remaining work (1-7/15) ? The question ask to find the fraction left.

Tricky said:   1 decade ago
Efficiency Method:

Total 60 unit.

A = 60/15 = 4.

B = 60/20 = 3.

Total = 7/60.

In 4 days = 4*7/60 = 28/60 = 7/15.

Remain = 1-7/15 = 8/15.

Vaibhav said:   1 decade ago
Why 1-7/15?

The total no. of work is 1 do 1-7/15.

If there are 2 works then 2-7/15.

If 3 works then 3-7/15.

And so on.

Sabaneak said:   1 decade ago
If remaining work is 8/15, how many days will it take A alone to complete the work.

Sweety said:   1 decade ago
A's 1 day's work = 1/15.

B's 1 day's work = 1/20.

(A + B) 's 1 day's work = (1+1) = 7.

15 20 60.

(A + B) 's 4 day's work = (7x1) = 7.

60 4 15.

Therefore, Remaining work = (1+7) = 8.

15 15.

Aravind_appu said:   1 decade ago
A = 1/15.
B = 1/20.

Together TH = A+B.

TH = (1/15+1/20).

TH/4 = (1/15+1/20).

TH = 4((35/15*20)).

TH = 7/15.

= 1-7/15 = 8/15.

Anand said:   1 decade ago
Balance work = 8/15.

A = 1/15, B = 1/20.

Total no of days required to complete remaining work.

A = (8/15) / (1/15) = 8 days,

B = (8/15) / (1/20) = 10 2/3 days.


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