Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 1)
1.
A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :

1
4

1
10

7
15

8
15

Answer: Option
Explanation:

A's 1 day's work = 1 ;
15

B's 1 day's work = 1 ;
20

(A + B)'s 1 day's work = ( 1 + 1 ) = 7 .
15 20 60

(A + B)'s 4 day's work = ( 7 x 4 ) = 7 .
60 15

Therefore, Remaining work = ( 1 - 7 ) = 8 .
15 15

Discussion:
347 comments Page 10 of 35.

Ni333 said:   1 decade ago
Thanks analyser.

Urmm said:   1 decade ago
L.C.M. of 15 & 20 are 60
and 60/15=4
and 60/20=3
so 4+3=7 as numerator
and 60 is denominator
OR
1/15+1/20=[(1*20)+(1*15)]/300=(20+15)/300=35/300=7/60
35 devide by 5 and 300 devide by 5

Pradeepshne said:   1 decade ago
Wow really superb.

Sangeetha said:   1 decade ago
Yes swetha your are right. Its very simple and easy method. Thank you.

Hashir Quraishi said:   1 decade ago
Swetha you rocked.

Gowtham said:   1 decade ago
How came remaining days?

Kamal said:   1 decade ago
I didn't undestand last step.

Akanksha said:   1 decade ago
(1/50+1/20) = (20+15)/300 //This get by cross multiplication.

= 35/300

= 7/60.

How did 300 came?

Neha garg said:   1 decade ago
Let total work is 1
1/15+1/20=x/4
7/60*4=x
that means x=7/15
1-7/15=8/15

Fouzia said:   1 decade ago
Fouzia.

How that 7 came I can't got it?


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