Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 17)
17.
A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days?
11 days
13 days

20 3 days
17

None of these
Answer: Option
Explanation:

Ratio of times taken by A and B = 100 : 130 = 10 : 13.

Suppose B takes x days to do the work.

Then, 10 : 13 :: 23 : x     =>     x = ( 23 x 13 )     =>     x = 299 .
10 10

A's 1 day's work = 1 ;
23

B's 1 day's work = 10 .
299

(A + B)'s 1 day's work = ( 1 + 10 ) = 23 = 1 .
23 299 299 13

Therefore, A and B together can complete the work in 13 days.

Discussion:
119 comments Page 5 of 12.

Ajay said:   6 years ago
First, solve percentage i.e-30% = 3/10.

From that fraction, we can calculate the efficiency of both A and B which is 13 and 10.
Work=time x efficiency.
Total work =23x13
Time is taken by both to do the work=23x13/23,
=13 days.

Shilajit Pramanik said:   9 years ago
A is 30% more efficient than B.

So B should the Base Value.

If B does the work in 100 days A should do it in 70 days.

Ratio of times taken by A and B = 70:100 = 7:10.

Please let me know if I am right.

Shilajit Pramanik.

Riad said:   8 years ago
In 1 day, B can do x portion of the work.

So, A can do 1.3x portion of the work.

So, 1.3x=1/23..x=1/(23*1.3) portion of the work.. together in 1 day can do. (1/23+1/29.9)...Then in 13 day they can complete the whole work.

Manasa said:   1 decade ago
@nayana
A can complete the work in 23 days.
A's 1 day work is 1/23
in similar manner
B can complete the work in 299/10 days
then B's 1 day work is 10/299
now they considered (A+B) 1 days work
therefore,(1/23)+(10/229)=1/13

Dibakar said:   1 decade ago
See A alone can do the work in 23 days which is 30% less than B.

So that means B does the work in 23+0.3*23=29.9.

Now A+B together will take:

1/23+1/29.9 = 529/(23*299) = 1/13.

So it will take both of them 13 days :).

Narayan said:   10 years ago
A = 30% of B.

Now 1 work two Man.

So, A + B = 1-------(1).

=> (30/100)B+B = 1.

=> 3B/10+B = 1.

=> 3B+10B = 10.

=> 13B = 10.

B = 10/13------(2).

(1) & (2) => A = 3/13.

Hence all total = 13 days.

Deepak said:   1 decade ago
WORKING DAYS FOR A = 23 DAYS,

IN ONE DAY A = 1/23,

Since A 30% efficient ,WORKING DAYS FOR B=23+23*30/100=299/10 DAYS.

IN ONE DAY B = 1/(299/10)=10/299.

(A+B)*DAY = 1.

(1/23+10/299)*DAY = 1.

DAY = 299/23 = 13 DAYS.

Tanuj Upadhyay said:   5 years ago
As given, A=B+(30% of B) i.e. A=(13B/10).

And, A=1/23 so put this value in the above equation.
We get, B=(10/23*13).
Now find, A+B => 1/23+10/23*13.
=> 1/23(1+10/13).

After solving it the value of A+B is (1/13).
(3)

AJAY D said:   1 week ago
A - 130.
B - 100.

130 23.
100 B.

130 * 23 = 100 * B,
130 * 23/100 = B.

A + B = 1/23 + 100/130 * 23.
= 130/130 * 23 + 100/130*23,
= 130 + 100/130 * 23,
= 230/130 * 23,
A + B = 1/13.

Ayush said:   5 years ago
If efficiency = a : b = 13:10.
Then time = 10:13.
10 tends to 23.,
1 ratio equal to 23/10.
A and B working together = 23*23/10.

And I got 529/10.

Whether this method is right or wrong? Please, anyone, tell me.
(2)


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