Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 17)
17.
A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days?
Answer: Option
Explanation:
Ratio of times taken by A and B = 100 : 130 = 10 : 13.
Suppose B takes x days to do the work.
Then, 10 : 13 :: 23 : x ![]() |
![]() |
23 x 13 | ![]() |
![]() |
299 | . |
10 | 10 |
A's 1 day's work = | 1 | ; |
23 |
B's 1 day's work = | 10 | . |
299 |
(A + B)'s 1 day's work = | ![]() |
1 | + | 10 | ![]() |
= | 23 | = | 1 | . |
23 | 299 | 299 | 13 |
Therefore, A and B together can complete the work in 13 days.
Discussion:
119 comments Page 3 of 12.
Shirisha said:
1 decade ago
I think it is 100:30 ans is wrong please explain how it is 100:130?
Prathyusha said:
1 decade ago
It is given that A is 30% efficient than B,it means that A can do better WORK than B, so the time time taken by A will obviously be less than by B.
So, their ratio of times taken by A and B will get reversed. (As from the problem).The ratio of A and B work is 130:100, but the time taken by them to complete will get reversed that is 100:130.
Thank you!
CORRECT ME IF I AM WRONG PLEASE!
So, their ratio of times taken by A and B will get reversed. (As from the problem).The ratio of A and B work is 130:100, but the time taken by them to complete will get reversed that is 100:130.
Thank you!
CORRECT ME IF I AM WRONG PLEASE!
Sree said:
1 decade ago
Why we consider 10:13::23:x ?
Shahid Basha said:
1 decade ago
Say B does a piece of work in 100 days.
Then as A is 30% more efficient has to complete the work in
100-(30/100)*100=70 days
A's 70 days work = B's 100 days work
so A's 1 day work = B's 100/70 days work
Therefore A's 23 days work = B's 2300/70 days Work
Which implies that 1 work is completed by B in 230/7 days
From this total work done by A & B in 1 day = (1/23)+(7/230)
=(10+7)/230
=17/230
So time taken to complete a work = 230/17=13.529 days
LET ME KNOW IF THIS IS WRONG OR EVEN RIGHT.
Then as A is 30% more efficient has to complete the work in
100-(30/100)*100=70 days
A's 70 days work = B's 100 days work
so A's 1 day work = B's 100/70 days work
Therefore A's 23 days work = B's 2300/70 days Work
Which implies that 1 work is completed by B in 230/7 days
From this total work done by A & B in 1 day = (1/23)+(7/230)
=(10+7)/230
=17/230
So time taken to complete a work = 230/17=13.529 days
LET ME KNOW IF THIS IS WRONG OR EVEN RIGHT.
Nayana said:
1 decade ago
In the problem while adding A+B why they have written 10/299 instead of writting 299/10 ?
Manasa said:
1 decade ago
@nayana
A can complete the work in 23 days.
A's 1 day work is 1/23
in similar manner
B can complete the work in 299/10 days
then B's 1 day work is 10/299
now they considered (A+B) 1 days work
therefore,(1/23)+(10/229)=1/13
A can complete the work in 23 days.
A's 1 day work is 1/23
in similar manner
B can complete the work in 299/10 days
then B's 1 day work is 10/299
now they considered (A+B) 1 days work
therefore,(1/23)+(10/229)=1/13
Shikha Sood said:
1 decade ago
I can explain why ratio 100:130 comes, as in problem it is given that A is 30% more effificient than B. That is A can do work in Less time so ratio By time will be A:B = 100:130 that is Time taken by A is 100 and B by 130 .......
Chethan said:
1 decade ago
A s 30% more eff...
i.e
A -> x(1+30/100) = 1/23
=> x(13/10) = 1/23
therefore
B -> x =10/299
add A+B u ll get 1/13
hence ans is 13
i.e
A -> x(1+30/100) = 1/23
=> x(13/10) = 1/23
therefore
B -> x =10/299
add A+B u ll get 1/13
hence ans is 13
Swetha said:
1 decade ago
A can do a work in 100 days
B can do a work in 130 days, since A is 30% more efficient than B.
Take LCM of 100 & 130.i.e 1300
A's per day capacity = 1300/100 = 13
B's per day capacity = 1300/130 = 10
Given that A alone can do the given work in 23 days.
Therefore ,work completed by A alone in 23 days = 13 x 23 = 299
if they work together, their per day capacity = 13 + 10 = 23
both together will complete the given work in 299/23 = 13 days
Ans : 13 days
B can do a work in 130 days, since A is 30% more efficient than B.
Take LCM of 100 & 130.i.e 1300
A's per day capacity = 1300/100 = 13
B's per day capacity = 1300/130 = 10
Given that A alone can do the given work in 23 days.
Therefore ,work completed by A alone in 23 days = 13 x 23 = 299
if they work together, their per day capacity = 13 + 10 = 23
both together will complete the given work in 299/23 = 13 days
Ans : 13 days
Hamsa said:
1 decade ago
Here why dont we use shortcut formula (K*X)/{(k^2)-1}???.
Can any one clear my doubt??
Can any one clear my doubt??
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