Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 26)
26.
A and B can do a work in 8 days, B and C can do the same work in 12 days. A, B and C together can finish it in 6 days. A and C together will do it in :
Answer: Option
Explanation:
(A + B + C)'s 1 day's work = | 1 | ; |
6 |
(A + B)'s 1 day's work = | 1 | ; |
8 |
(B + C)'s 1 day's work = | 1 | . |
12 |
![]() |
|
||||||||||||||
|
|||||||||||||||
|
|||||||||||||||
|
So, A and C together will do the work in 8 days.
Discussion:
53 comments Page 4 of 6.
Gregory wachiye said:
9 years ago
This is awesome. I have gained a lot with the help of this explanations.
Nandhu said:
8 years ago
a+b=8,b+c=12,a+b+c=6.
LCM(8,12,6)=24.
a+b=24/8=3,b+c=24/12=2,a+b+c=24/6=4,
(a+b+c)-(a+b)=1,(a+b+c)-(b+c)=2,
c=1 a=2.
a+c=3,24/3=8.
ans:8.
LCM(8,12,6)=24.
a+b=24/8=3,b+c=24/12=2,a+b+c=24/6=4,
(a+b+c)-(a+b)=1,(a+b+c)-(b+c)=2,
c=1 a=2.
a+c=3,24/3=8.
ans:8.
(1)
Dimple said:
8 years ago
Thank you for all your explanations.
Vikas said:
8 years ago
Thanks for the explanation.
Deep said:
7 years ago
Thanks @Parveen.
Santosh said:
7 years ago
A+B ....8 DAY- 3unit. L.C.M-24 UNIT
B+C......12 DAY - 2 unit.
A+B+C......6 DAY -(24/6)...4 unit .
Then,
A+B+C=4. A+B=3....(3+C=4 =C=1)
C=1.
B+C=2 UNIT .....C=1.
B=1.
A+B=3.
B=1.
A=2 .
A and c's work.
A+c=2+1=3 unit per day,
Total work =24 unit,
A+c=24/3=8 day.
B+C......12 DAY - 2 unit.
A+B+C......6 DAY -(24/6)...4 unit .
Then,
A+B+C=4. A+B=3....(3+C=4 =C=1)
C=1.
B+C=2 UNIT .....C=1.
B=1.
A+B=3.
B=1.
A=2 .
A and c's work.
A+c=2+1=3 unit per day,
Total work =24 unit,
A+c=24/3=8 day.
Chary said:
7 years ago
good explanation, thanks all.
Rohit kushwaha said:
7 years ago
Thank you @Bhanu.
Nav said:
7 years ago
Why can't we simply subtract A+B's 1-day work from B+C's 1-day work to get A+C's 1-day work?
Ricky nahar said:
7 years ago
@Nandhu.
Why a=2?
Why a=2?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers