Aptitude - Time and Work - Discussion

A = 16 Days.
B = 12 Days.
A+B+C = 4 Days.
C = ?
1st of all we take LCM of 16, 12, and 4.
LCM of 16,12 and 4 is 48.
It means whole work is 48 unit then we find the unit of per day of all.
A = 48/16 = 3unit/day.
B = 48/12 = 4unit/day.
A+B+C = 48/4 = 12unit/day.
A+B = 3+4 = 7unit/day.

Now subtract from (A+B+C)-(A+B)=12-7 = 5.
C = 5unit/day.
It means C can alone of whole work is 48/5 days.

According to me,
a+b+c=4
a=16
b=12
c=?

C = a * b/b-c,
=16 * 12/16-12,
= 16 * 12/4,
=4 * 12 = 48.

Am I correct?

How is possible at 5/48 write 48/5? please solve it for me.

@Shruti.

A's one day work = 1/16.
B's one day work = 1/12.
with the help of C , they finished in 4 days.
So, A+B+C=4 days,
Therefore, (A+B+C)'s one day work = 1/4.
If C alone is = X.
then 1/16+1/12+X = 1/4,
X= 1/4-(1/16+1/12) {Lcm of 16, 12 is 48 and by the cross multiplication will get 7/48}
= 1/4-7/48,
= 12-7/48,
= 5/48,
C's one day work = 5/48.

I didn't get still that how 5/48 came from 28/192, actually, I don't know the basics to solve maths so please explain.

Guys don't be confused.

A can do in 16 days.
B can do in 12 days.
A B & C can do in 4 days.

So,
Total work is to be done is 48.
( lcm of all)
Then A's efficiency is 3.
B's effc is 4.
A B n C effc is 12.
So, A + B + C = 12
4 + 3 + C = 12
7 + c = 12
C = 5.

Then 5/48 or 48/5.

Thanks for clarifying the solution @Ajay.

@Shantanu

Thank you, you are right.

Actually, A can solve in 16 days for one day it will be 1/16. if we take for 2 days work it will become 2/16. in the same way the work done by c per day is 5/48. If you want total work done by 'c' just reverse the fraction like 48/5.

Ex: THE TOTAL WORK DONE BY 'B' IS IN 12DAYS, FOR ONE DAY 12,IN THE SCENE 12/1. You should remember that 5/48 is the work done by 'c' in one day.

A's efficiency = 3, and B's efficiency =4, so (3 + 4) = 5 then C's efficiency (12 - 7) =5, So total work take LCM of (16, 12, 4) = 48, so C alone finished the work 48/5.

A can complete 1/16th of the work in 1 day.

B can complete 1/12th of the work in 1 day.

Let C complete 1/Xth of the work in 1 day.

So, A, B & C can complete (1/16 + 1/12 + 1/X)th part of the work in 1 day.

Therefore in 4 days, they together can complete = 4*(1/16 + 1/12 + 1/X)th part of the work . Always remember & denote work completed as 1.

On solving 4*(1/16 + 1/12 + 1/X) = 1, you can get the value of x which is the number of days taken by C to do the work.

Hope it helps you.