Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 2)
2.
A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in:
Answer: Option
Explanation:
| (A + B + C)'s 1 day's work = | 1 | , |
| 4 |
| A's 1 day's work = | 1 | , |
| 16 |
| B's 1 day's work = | 1 | . |
| 12 |
 C's 1 day's work = |
1 | - |  |
1 | + | 1 |  |
= | |
1 | - | 7 | |
= | 5 | . |
| 4 | 16 | 12 | 4 | 48 | 48 |
| So, C alone can do the work in | 48 | = 9 | 3 | days. |
| 5 | 5 |
Discussion:
224 comments Page 6 of 23.
Shashi said:
6 years ago
A = 16.
B = 12.
Lcm for 16,12 is 48.
16*3 = 48.
12*4 = 48.
With the help of c they did the job in 4 days only,
So 48/4=12.
12-(a+b).
12-(3+4) = 5
Now 48/5 = 9.6 hrs.
B = 12.
Lcm for 16,12 is 48.
16*3 = 48.
12*4 = 48.
With the help of c they did the job in 4 days only,
So 48/4=12.
12-(a+b).
12-(3+4) = 5
Now 48/5 = 9.6 hrs.
Sai kumar Reddy Nossam said:
7 years ago
common multiple for 12 and 16 is 48.
A's one day work =48/16=3 units,
B's one day work=48/12=4 units,
C's one day work??
A and B together do a piece of work in 4 days= 28 units.
remaining work ( C's work in 4 days)=48 - 20 =20 units,
C's work in one day=20/4=5 unit,
C alone can do the job in=(5 * 9)+3/5 = 9 3/5.
A's one day work =48/16=3 units,
B's one day work=48/12=4 units,
C's one day work??
A and B together do a piece of work in 4 days= 28 units.
remaining work ( C's work in 4 days)=48 - 20 =20 units,
C's work in one day=20/4=5 unit,
C alone can do the job in=(5 * 9)+3/5 = 9 3/5.
Shivani said:
7 years ago
A can do the work = 16 days,
B can do the work =12days,
A+B+C together can do work =4 days.
let's take the LCM of 16,12 and 4 it is 48.
calculate the 1 day's work of A,B and A+B+C,
1day's work of A= 48/16= 3,
1day's work of B= 48/12= 4,
1day's work of A+B+C =48/4=12,
Here we calculate the 1day's work of c,
A+B+C=12,
3+4+C=12,
7+C=12,
C=12-7,
C=5.
Then,
c alone can do the work in;
C = 48/5 = 9 * 3/5 days.
B can do the work =12days,
A+B+C together can do work =4 days.
let's take the LCM of 16,12 and 4 it is 48.
calculate the 1 day's work of A,B and A+B+C,
1day's work of A= 48/16= 3,
1day's work of B= 48/12= 4,
1day's work of A+B+C =48/4=12,
Here we calculate the 1day's work of c,
A+B+C=12,
3+4+C=12,
7+C=12,
C=12-7,
C=5.
Then,
c alone can do the work in;
C = 48/5 = 9 * 3/5 days.
Anish said:
7 years ago
@Sunshine.
In the question, it was mentioned that B and C can finish the work in 12 days not only A.
then how you can said B's work = 12 days?
Please explain the step.
In the question, it was mentioned that B and C can finish the work in 12 days not only A.
then how you can said B's work = 12 days?
Please explain the step.
Sunshine said:
7 years ago
A work = 16 days.
B work = 12 days.
Total work was done by A and B = 48 unit (LCM Of A and B).
So work done by A in one day = 48/16= 3 unit.
And work was done by B in one day = 48/12 = 4 unit.
So work done by A and B in 1 day = 3+4 = 7 unit.
Work was done by A and B in 4 days = 7*4 = 28 unit.
So remaining work = 48-28 = 20 unit.
So work done by C in one day= 20/4 = 5 unit.
So, the total work was done by C in days = 48/5 days =9*3/5 days.
B work = 12 days.
Total work was done by A and B = 48 unit (LCM Of A and B).
So work done by A in one day = 48/16= 3 unit.
And work was done by B in one day = 48/12 = 4 unit.
So work done by A and B in 1 day = 3+4 = 7 unit.
Work was done by A and B in 4 days = 7*4 = 28 unit.
So remaining work = 48-28 = 20 unit.
So work done by C in one day= 20/4 = 5 unit.
So, the total work was done by C in days = 48/5 days =9*3/5 days.
Aruva said:
7 years ago
Thank you @Soujanya.
Suchi said:
7 years ago
Thank you @Siba.
Pooja said:
7 years ago
As per formula: If A completes 1/n work in 1 day then the days required by him to complete that 1 work alone will be 1 ÷ 1/n = n days.
Similarly, C can complete 5/48 part of the work in a day. To complete 1 work alone he will take 1 ÷ 5/48 days to 48/5.
Similarly, C can complete 5/48 part of the work in a day. To complete 1 work alone he will take 1 ÷ 5/48 days to 48/5.
Jaga said:
7 years ago
Thanks @Aanurag.
Siba siddquie said:
7 years ago
A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in:
LCm of A,B,A+B+C (16,12,4)=total work=48...;;
A' 1 day work=48/16=3;
same B=48/12=4..A+B+C=48/4=12,
A+B+C=12,
3+4+C=12,
C 'one day work =5,
total work is =48.
C completes the work in (days) = total work/one day work..(formula) = 48/5=9(3/5) => answer.
LCm of A,B,A+B+C (16,12,4)=total work=48...;;
A' 1 day work=48/16=3;
same B=48/12=4..A+B+C=48/4=12,
A+B+C=12,
3+4+C=12,
C 'one day work =5,
total work is =48.
C completes the work in (days) = total work/one day work..(formula) = 48/5=9(3/5) => answer.
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