Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 2)
2.
A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in:
Answer: Option
Explanation:
| (A + B + C)'s 1 day's work = | 1 | , |
| 4 |
| A's 1 day's work = | 1 | , |
| 16 |
| B's 1 day's work = | 1 | . |
| 12 |
C's 1 day's work = |
1 | - | ![]() |
1 | + | 1 | ![]() |
= | ![]() |
1 | - | 7 | ![]() |
= | 5 | . |
| 4 | 16 | 12 | 4 | 48 | 48 |
| So, C alone can do the work in | 48 | = 9 | 3 | days. |
| 5 | 5 |
Discussion:
226 comments Page 19 of 23.
Kaustav said:
1 decade ago
One step equation:1/16+1/12+1/x=1/4.
Prachi said:
1 decade ago
Can you explain me why 5/48 reverse?
Vikas said:
8 years ago
1/4-7/48= 5/48 how? Please explain.
Sangmesh said:
4 years ago
5/48 how this came? Please explain.
(1)
Karthick said:
5 years ago
How did come 5/48? Explain please.
Sowjanya said:
1 decade ago
Thanks geeta you solved my doubt.
Mohammed aqib said:
1 decade ago
In equation 5/48 how did 5 arise?
Khizer said:
1 decade ago
= 1/16+1/12+1/C = 1/4.
C = 48/5.
C = 48/5.
Gurjit said:
1 decade ago
Why did you write 5/48 as 48/5 ?
AMIT said:
1 decade ago
How the fractional 7/48 arrived?
(1)
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C's 1 day's work =
