Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 2)
2.
A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in:
Answer: Option
Explanation:
| (A + B + C)'s 1 day's work = | 1 | , |
| 4 |
| A's 1 day's work = | 1 | , |
| 16 |
| B's 1 day's work = | 1 | . |
| 12 |
C's 1 day's work = |
1 | - | ![]() |
1 | + | 1 | ![]() |
= | ![]() |
1 | - | 7 | ![]() |
= | 5 | . |
| 4 | 16 | 12 | 4 | 48 | 48 |
| So, C alone can do the work in | 48 | = 9 | 3 | days. |
| 5 | 5 |
Discussion:
226 comments Page 13 of 23.
Mahesh sawant said:
1 decade ago
Please explain how come 5/48?
Pundir said:
1 decade ago
All the explanations are really amazing and understandable. But I would like to add a point to the discussion. Why did we do 1/16, 1/12 or 1/4. See there is lot frequency distribution in the values. So to ease our lives we want to compare all this to a benchmark value.
In this case everybody is taking different number of duration's to complete a particular task. So first we want to find out how much work everybody was able to complete in any particular day. Just to make the calculations easier.
And if one can do (1/16)th part of a work in one day, then just by reversing the fraction we can get to know in total how many days he/she will be able to complete the entire task.
Hope this will help.
In this case everybody is taking different number of duration's to complete a particular task. So first we want to find out how much work everybody was able to complete in any particular day. Just to make the calculations easier.
And if one can do (1/16)th part of a work in one day, then just by reversing the fraction we can get to know in total how many days he/she will be able to complete the entire task.
Hope this will help.
Naresh said:
1 decade ago
How do you get 1/4?
GAUTAM said:
1 decade ago
Answer of C work 5/48 to 48/5.
This is one day work of C.
Example as given in question itself.
A work complete in 16 day so in 1 day 'a' will complete 1/16 portion of whole work. Whole work completed by a is 16/1=16 days.
This is one day work of C.
Example as given in question itself.
A work complete in 16 day so in 1 day 'a' will complete 1/16 portion of whole work. Whole work completed by a is 16/1=16 days.
Sasmita said:
1 decade ago
Tell me any one that c's work. I can't understand it.
Harmit said:
1 decade ago
Easiest method.
LCM is 48 of 16 &12. Then A can complete work in 3 work and B can 4 work.
Now A B C can complete 12 work.
Now A and B complete 7 work so still remaining work is 5.
So C can alone complete work 48/5. So answer is C. You can easily calculate.
LCM is 48 of 16 &12. Then A can complete work in 3 work and B can 4 work.
Now A B C can complete 12 work.
Now A and B complete 7 work so still remaining work is 5.
So C can alone complete work 48/5. So answer is C. You can easily calculate.
Emma said:
1 decade ago
Where does 48 come from in this come equation?
Abi said:
1 decade ago
A can do work in 16 days.
Then, A's 1 day work = 1/16.
Meanwhile, C's 1 day work = 5/48 (our ans).
Then, C can do work in 48/5 days.
Then, A's 1 day work = 1/16.
Meanwhile, C's 1 day work = 5/48 (our ans).
Then, C can do work in 48/5 days.
Ankit said:
1 decade ago
How to change this 5/48 to 48/5?
Soumya said:
1 decade ago
@Deepika.
C's 1 day work is 5/48.
Here we require C's total work.
Total work should be taken as '1'.
So, 1 day work i.e,5/48*number of days used to complete the work(unknown, so take it as 'x') = total work 1.
Simply, 5/48*x = 1.
5x = 48.
x = 48/5.
So C's total work is 48/5.
C's 1 day work is 5/48.
Here we require C's total work.
Total work should be taken as '1'.
So, 1 day work i.e,5/48*number of days used to complete the work(unknown, so take it as 'x') = total work 1.
Simply, 5/48*x = 1.
5x = 48.
x = 48/5.
So C's total work is 48/5.
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C's 1 day's work =
