Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 12)
12.
4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it?
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 woman's 1 day's work = y.
| Then, 4x + 6y = | 1 | and 3x + 7y = | 1 | . |
| 8 | 10 |
| Solving the two equations, we get: x = | 11 | , y = | 1 |
| 400 | 400 |
 1 woman's 1 day's work = |
1 | . |
| 400 |
 10 women's 1 day's work = |
 |
1 | x 10 |  |
= | 1 | . |
| 400 | 40 |
Hence, 10 women will complete the work in 40 days.
Discussion:
106 comments Page 7 of 11.
Mamatha said:
1 decade ago
6/400 = 3/200.
Take LCM of 1/8-3/200 = 440/4000 = 11/100.
Is it clear?
Take LCM of 1/8-3/200 = 440/4000 = 11/100.
Is it clear?
Abdul said:
1 decade ago
How can this problem be solved if the supporting statement isn't given, that is "3 men and 7 women complete work in 10 days. ".
What if the question is "4 men and 6 women can complete the work in 8 days then how many days it will take for 10 women to finish the work?".
What if the question is "4 men and 6 women can complete the work in 8 days then how many days it will take for 10 women to finish the work?".
Xxx said:
1 decade ago
LCM of 1/8-3/200 = 440/4000 = 11/100.
How can possible 8, 200 LCM is 4000. I am not understand please explain?
How can possible 8, 200 LCM is 4000. I am not understand please explain?
Narasingarao said:
1 decade ago
men | women = days.
4 | 6 = 8.
3 | 7 = 10.
| 10 = ?
Solution- by cross multiplication and subtraction.
6*10 = 60 ; 4*7 = 28.
7*8 = 56 ; 3*6 = 18.
60-56 = 4 * 28-18 = 10 = 4*10 = 40 days.
4 | 6 = 8.
3 | 7 = 10.
| 10 = ?
Solution- by cross multiplication and subtraction.
6*10 = 60 ; 4*7 = 28.
7*8 = 56 ; 3*6 = 18.
60-56 = 4 * 28-18 = 10 = 4*10 = 40 days.
Deepak Patgar said:
1 decade ago
Abdul if the supportive statement is not given it can never be solved as we don't know man and woman work proportion.
Manu said:
1 decade ago
Please can you explain how to get x = 11/400 and y = 1/400.
Sharad said:
1 decade ago
@Manu.
4x+6y = 1/8.............1.
3x+7y = 1/10............2.
For canceling term x we can multiply 1 by 3 and equation 2 by 4. Then we got:
12x+18y = 3/4...........3.
12x+28y = 4/10.........4.
Then subtract equation 4 by equation 3.
y = 1/100.
Put y in equation 1.
y = 1/400.
4x+6y = 1/8.............1.
3x+7y = 1/10............2.
For canceling term x we can multiply 1 by 3 and equation 2 by 4. Then we got:
12x+18y = 3/4...........3.
12x+28y = 4/10.........4.
Then subtract equation 4 by equation 3.
y = 1/100.
Put y in equation 1.
y = 1/400.
Saurabh said:
1 decade ago
@Narasingarao please explain your method?
Deepika said:
1 decade ago
Please explain how to solve these two equations? Explain with it in step by step?
Raman said:
1 decade ago
Can anyone please solve this by LCM method?
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