Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 12)
12.
4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it?
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 woman's 1 day's work = y.
| Then, 4x + 6y = | 1 | and 3x + 7y = | 1 | . |
| 8 | 10 |
| Solving the two equations, we get: x = | 11 | , y = | 1 |
| 400 | 400 |
 1 woman's 1 day's work = |
1 | . |
| 400 |
 10 women's 1 day's work = |
 |
1 | x 10 |  |
= | 1 | . |
| 400 | 40 |
Hence, 10 women will complete the work in 40 days.
Discussion:
106 comments Page 6 of 11.
Ami said:
1 decade ago
4x+6y=1/8 ----(1)
3x+7y=1/10 ----(2)
now,multiply equation 1 with 3 and equ.2 with 4
12x+18y=3/8
12x+28y=2/5
- - -
-------------
-10y=-1/40
10y=1/40 so, 40 become ans
3x+7y=1/10 ----(2)
now,multiply equation 1 with 3 and equ.2 with 4
12x+18y=3/8
12x+28y=2/5
- - -
-------------
-10y=-1/40
10y=1/40 so, 40 become ans
Afia Sharmin said:
1 decade ago
Answer for: 6 men and 8 women can do a work in 18 days. How many days will it require to complete the whole work if 3 men and 5 women work together?
Jayalakshmi said:
1 decade ago
Can you please explain.
How comes.
4x + 6y = 1/8 and 3x + 7y = 1/10.
X = 11/400, y = 1/400.
In easy method above mentioned methods are very difficult to understand.
How comes.
4x + 6y = 1/8 and 3x + 7y = 1/10.
X = 11/400, y = 1/400.
In easy method above mentioned methods are very difficult to understand.
Syed said:
1 decade ago
4M+6W=8 ----1
3M+7W=10 ----2
10W = ? ----3
8*4M+8*6w = 10*3M+10*7W
32M+48W = 30M+70W
32M-30M = 70W-48W
2M = 22W
1M = 11W
PUT IN EQ-2.
33W+7W = 10
40W = 10
40*10= 10*?
?= 40.
3M+7W=10 ----2
10W = ? ----3
8*4M+8*6w = 10*3M+10*7W
32M+48W = 30M+70W
32M-30M = 70W-48W
2M = 22W
1M = 11W
PUT IN EQ-2.
33W+7W = 10
40W = 10
40*10= 10*?
?= 40.
Vinod Anand said:
1 decade ago
If 4M+6w = 1/8 ---- (1)x 3.
3M+7w = 1/10 ----(2)x 4.
And
12M+18W = 3/18.
12M+28w = 4/10.
Than
10W = 2/5 - 3/8 = 1/40.
Answer 10 W = 40, Option (B).
3M+7w = 1/10 ----(2)x 4.
And
12M+18W = 3/18.
12M+28w = 4/10.
Than
10W = 2/5 - 3/8 = 1/40.
Answer 10 W = 40, Option (B).
Adnan said:
1 decade ago
One day work by 4M + 6W = 1\8 --- (1).
One day work by 3M + 7W = 1\10 --- (2).
10W = ?
Multiply (1) by 3 and (2) by 4
12M + 18W = 3/8 => 12M = 3/8 - 18W --- (3).
12M + 28W = 4/10 => 12M + 28W = 2/5 --- (4).
Putting 12M value from (3) to (4)
3/18 - 18W + 28W = 2/5.
10W = 2/5 - 3/8.
10W = 1/40.
Since one day work by 10W = 1/40.
Hence, 10 women will complete the work in 40 days.
One day work by 3M + 7W = 1\10 --- (2).
10W = ?
Multiply (1) by 3 and (2) by 4
12M + 18W = 3/8 => 12M = 3/8 - 18W --- (3).
12M + 28W = 4/10 => 12M + 28W = 2/5 --- (4).
Putting 12M value from (3) to (4)
3/18 - 18W + 28W = 2/5.
10W = 2/5 - 3/8.
10W = 1/40.
Since one day work by 10W = 1/40.
Hence, 10 women will complete the work in 40 days.
Suresh said:
1 decade ago
Hi guys, Kindly solve those two equation in step by step with simple format.
Jak said:
1 decade ago
Hi I can't understand this problem.
Can we solve like this way.
4 man and 6 women = 8 days.
3 man and 7 women = 10 days.
So,
2 man and 8 women = 12 days.
1 man and 9 women = 14 days.
0 man and 10 women = 16 days.
Is it right way.
Can we solve like this way.
4 man and 6 women = 8 days.
3 man and 7 women = 10 days.
So,
2 man and 8 women = 12 days.
1 man and 9 women = 14 days.
0 man and 10 women = 16 days.
Is it right way.
Avinash Singh said:
1 decade ago
I have a best answer:
4M + 6W = 8 days.
32M + 48W = 1 day --- 1.
3M + 7W = 10 days.
30M + 70W = 1 day ----2.
From 1 and 2, we get.
2M = 22W.
1M = 11W.
and also 3M = 33W.
Subs in 3M + 7W = 10 days.
we get, 33W + 7W = 10 days.
40W = 10 days.
Then,
10W = 40 days.
4M + 6W = 8 days.
32M + 48W = 1 day --- 1.
3M + 7W = 10 days.
30M + 70W = 1 day ----2.
From 1 and 2, we get.
2M = 22W.
1M = 11W.
and also 3M = 33W.
Subs in 3M + 7W = 10 days.
we get, 33W + 7W = 10 days.
40W = 10 days.
Then,
10W = 40 days.
Suma said:
1 decade ago
Hi, can anybody explain how comes 1/8-6/400 =11/100?
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