Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Answer: Option
Explanation:
| A's 2 day's work = |  |
1 | x 2 |  |
= | 1 | . |
| 20 | 10 |
| (A + B + C)'s 1 day's work = | |
1 | + | 1 | + | 1 | |
= | 6 | = | 1 | . |
| 20 | 30 | 60 | 60 | 10 |
| Work done in 3 days = | |
1 | + | 1 | |
= | 1 | . |
| 10 | 10 | 5 |
| Now, | 1 | work is done in 3 days. |
| 5 |
Whole work will be done in (3 x 5) = 15 days.
Discussion:
361 comments Page 6 of 37.
Abhishek said:
2 decades ago
@chirag:
Step 3 gives work done in first 3 day i.e. work done in 1st day + work done in 2nd day +work done in 3rd day = 1/20 (by A alone) + 1/20 (by B alone) + 1/10 (done by A, B and C together)
Similarly they continue and as per the question on every 3rd day A is joined by B and C.
Step 3 gives work done in first 3 day i.e. work done in 1st day + work done in 2nd day +work done in 3rd day = 1/20 (by A alone) + 1/20 (by B alone) + 1/10 (done by A, B and C together)
Similarly they continue and as per the question on every 3rd day A is joined by B and C.
Nitesh Nandwana said:
2 decades ago
Hi chirag don't go on step, here our aim is to compute total work done in 3 days once, first 2 days A is working alone and last 3rd day we are adding work's of B and C.
Sushant said:
2 decades ago
(A + B + C)'s 1 day's work = 1 + 1 + 1 = 6 = 1 .
20 30 60 60 10
how did we get 60
20 30 60 60 10
how did we get 60
Bala said:
2 decades ago
I can't get this.
Dhanam said:
2 decades ago
Why are you taking 2 days for first step?
Vishnu said:
2 decades ago
Why you have taken the a+b+c? A is assisted by only B, C know.
Anbu said:
2 decades ago
How you got 6/60?
I think the answer is 12.
I think the answer is 12.
Beeribrahim said:
2 decades ago
How it is user
Now, 1 work is done in 3 days.
5
Whole work will be done in (3 x 5) = 15 days.
Now, 1 work is done in 3 days.
5
Whole work will be done in (3 x 5) = 15 days.
Shreekanth said:
2 decades ago
@Vishnu...
As per the statement A will do the work three days continuosly but only on third day B & C will assist, so
A's thrid day work must also include with both B & C
that's why...
(A + B + C)'s 1 day's work is taken
As per the statement A will do the work three days continuosly but only on third day B & C will assist, so
A's thrid day work must also include with both B & C
that's why...
(A + B + C)'s 1 day's work is taken
Vijay said:
2 decades ago
1/20+1/(30X3)+1/(60X3) = 1/15
Is my way of solving correct?
Is my way of solving correct?
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