Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Answer: Option
Explanation:
A's 2 day's work = | ![]() |
1 | x 2 | ![]() |
= | 1 | . |
20 | 10 |
(A + B + C)'s 1 day's work = | ![]() |
1 | + | 1 | + | 1 | ![]() |
= | 6 | = | 1 | . |
20 | 30 | 60 | 60 | 10 |
Work done in 3 days = | ![]() |
1 | + | 1 | ![]() |
= | 1 | . |
10 | 10 | 5 |
Now, | 1 | work is done in 3 days. |
5 |
Whole work will be done in (3 x 5) = 15 days.
Discussion:
357 comments Page 33 of 36.
Bralow said:
1 decade ago
Why we multiply 3*5 in last step?
Mir sakib said:
1 decade ago
What is its mean every third day?
Jayshri said:
6 years ago
How got the 3rd step (1/10+1/10)?
Chitra.G said:
1 decade ago
Why we take 2 days? Please help.
Shanmugapriya said:
8 years ago
Nice explanation, Thanks @Vijay.
RAJA said:
5 months ago
Why have to take 3 days of work?
(18)
Amey said:
1 decade ago
Why we are multiplying 3 by 5 ?
Nazam said:
7 years ago
How did (1/10+1/10) = 1/5 came?
Ashwini said:
1 decade ago
Can you explain how 6/60 came?
Priya said:
10 years ago
How to solve (1/20+1/30+1/60)?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers