Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Answer: Option
Explanation:
| A's 2 day's work = |  |
1 | x 2 |  |
= | 1 | . |
| 20 | 10 |
| (A + B + C)'s 1 day's work = | |
1 | + | 1 | + | 1 | |
= | 6 | = | 1 | . |
| 20 | 30 | 60 | 60 | 10 |
| Work done in 3 days = | |
1 | + | 1 | |
= | 1 | . |
| 10 | 10 | 5 |
| Now, | 1 | work is done in 3 days. |
| 5 |
Whole work will be done in (3 x 5) = 15 days.
Discussion:
357 comments Page 30 of 36.
Sindhuja said:
1 decade ago
@monoj.
Superb explanation.
Superb explanation.
Naari said:
1 decade ago
@vikas.
Good work dude.
Good work dude.
Tania said:
1 decade ago
@kamalakannan
Because A alone does the work in FIRST day and in 3rd day he takes the help of B, C. So 1st A's 2daz work is calculated.
Because A alone does the work in FIRST day and in 3rd day he takes the help of B, C. So 1st A's 2daz work is calculated.
Renjini said:
1 decade ago
How could get 1/5? I can't understand.
Eswarijana said:
1 decade ago
I can't understand the last step.
Kamalakannan said:
1 decade ago
Could you tell me? why you take A has done by 2 days work?
Siddu said:
1 decade ago
Please explain how we will get 6/60 please?
Anitha said:
1 decade ago
Why we have to calculate A's days work? Explain any one please.
Hitesh said:
1 decade ago
work done by A per day=1/20;
work done by B per day=1/30;
work done by C per day=1/60;
Let the work is completed in 3x days
So,
1/20*3x+1/30*x+1/60*x=1
=> x=5
=> No. of days required to complete the work=3*5=15days
work done by B per day=1/30;
work done by C per day=1/60;
Let the work is completed in 3x days
So,
1/20*3x+1/30*x+1/60*x=1
=> x=5
=> No. of days required to complete the work=3*5=15days
Kv manikanta said:
1 decade ago
How do you say that A's work is 2 days it means how it came 2 (1/20) = 1/10.
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